hdu 2516 取石子游戏 (博弈)

取石子游戏

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2328    Accepted Submission(s): 1328

Problem Description

1堆石子有n个,两人轮流取.先取者第1次可以取任意多个，但不能全部取完.以后每次取的石子数不能超过上次取子数的2倍。取完者胜.先取者负输出"Second win".先取者胜输出"First win".

Input

输入有多组.每组第1行是2<=n<2^31. n=0退出.

Output

先取者负输出"Second win". 先取者胜输出"First win". 
参看Sample Output.

Sample Input

2
13
10000
0

Sample Output

Second win
Second win
First win

Source

ECJTU 2008 Autumn Contest

Recommend

lcy   |   We have carefully selected several similar problems for you:  2509 2512 2510 1524 2515 

 //0MS    232K    345 B    G++
 /*

     先取为负的情况符合斐波那契数列. 

 */
 #include<stdio.h>
 int main(void)
 {
     int n;
     int a[]={,};
     for(int i=;i<;i++)
         a[i]=a[i-]+a[i-];
     while(scanf("%d",&n),n)
     {
         int flag=;
         for(int i=;i<;i++)
             if(n==a[i]) flag=;
         if(flag) puts("Second win");
         else puts("First win");
     }
     return ;
 }