分割两个整数产生一个浮点结果[重复]

Possible Duplicate:
Why can't I return a double from two ints being divided

可能重复:为什么我不能从被分割的两个ints返回一个double

My C++ program is truncating the output of my integer devision even when I try and place the output into a float. How can I prevent this whilst keeping those to variables (a & b) as integers?

我的c++程序正在截断我的整数devision的输出，即使我尝试将输出放入一个浮点数。如何在保持变量(a和b)为整数的同时避免这种情况?

user@box:~/c/precision$ cat precision.cpp
#include <iostream>
#include <iomanip>
using namespace std;

int main()
{
  int a = 10, b = 3;
  float ans = (a/b);
  cout<<fixed<<setprecision(3);
  cout << (a/b) << endl;
  cout << ans << endl;
  return 0;
}

user@box:~/c/precision$ g++ -o precision precision.cpp 
user@box:~/c/precision$ ./precision 
3
3.000

1 个解决方案

#1

Cast the operands to floats:

将操作数转换为浮点数:

float ans = (float)a / (float)b;