一个双重的javascript函数来转换一个长日期并以mm-dd-yyyy格式返回今天的日期

时间:2023-01-14 14:24:04

I need your help,

我需要你的帮助,

I can't seem to find any other help on this on the internet, because it seems its either one way ot the other. What I would like to be able to do is to create a combined, two-fold javascript function that would convert a long date string into the mm-dd-yyyy format, and when the same function is called again with no string specified to convert, to just return todays date in mm-dd-yyyy format.

我似乎无法在互联网上找到任何其他帮助,因为它似乎是另一种方式。我希望能够做的是创建一个组合的,双重的javascript函数,它将长日期字符串转换为mm-dd-yyyy格式,并且当再次调用相同的函数时没有指定要转换的字符串,以mm-dd-yyyy格式返回今天的日期。

Example:

getDate(Fri May 22 2015 13:32:25 GMT-0400)

would return: 05-22-2015

将返回:2015年5月22日

getDate()

would return today's date of 05-23-2015

将于今天05-23-2015返回

3 个解决方案

#1


0  

Hi this should do the trick

嗨,这应该做的伎俩

FORMAT: mm-dd-yyyy

function addZeroIfRequired(dayOrMonth) {
    return dayOrMonth > 9 ? dayOrMonth : "0"+dayOrMonth;
}

function getDate(dateString) {
   var date = dateString ? new Date(dateString) : new Date();
   return addZeroIfRequired((date.getUTCMonth()+1)) + "-" + 
          addZeroIfRequired(date.getDate())+  "-" + 
          date.getUTCFullYear();
}

console.log(getDate()); // 05-23-2015
console.log(getDate("Fri May 22 2015 13:32:25 GMT-0400")); 05-22-2015

NOTE: the +1 after the getUTCMonth().

注意:getUTCMonth()之后的+1。

JSFiddle. Open the console to see the result. https://jsfiddle.net/wt79yLo0/2/

的jsfiddle。打开控制台以查看结果。 https://jsfiddle.net/wt79yLo0/2/

ISO FORMAT: yyyy-mm-dd

ISO格式:yyyy-mm-dd

Just in case someone is interested in the opposite format, the code would be much nicer and neater:

为了防止有人对相反的格式感兴趣,代码会更好更整洁:

function getDate(dateString) {
   var date = dateString ? new Date(dateString) : new Date();
   return date.toISOString().substring(0, 10);
}

console.log(getDate());
console.log(getDate("Fri May 22 2015 13:32:25 GMT-0400"));

https://jsfiddle.net/wt79yLo0/

#2


0  

First I would recommend a very powerful library for JS called Moment.js which solves all this kind of problems.

首先,我会推荐一个非常强大的JS库,名为Moment.js,它解决了所有这些问题。

But if you only want a snippet, here is my proposal:

但如果你只想要一个片段,这是我的建议:

function twoDigits(num) { 
    return ("0" + num).substr(-2); 
}

function getFormattedDateDMY(date, separator) {
    var day = twoDigits(date.getDate());
    var month = twoDigits(date.getMonth());
    var year = date.getFullYear();
    return [day,month,year].join(separator);
}

function getFormattedDateMDY(date, separator) {
    var day = twoDigits(date.getDate());
    var month = twoDigits(date.getMonth());
    var year = date.getFullYear();
    return [month,day,year].join(separator);
}

console.log(getFormattedDateDMY(new Date(), "-"));  //23-04-2015
console.log(getFormattedDateMDY(new Date(), "-"));  //04-23-2015

#3


0  

With getDate(), getMonth() and getFullYear(). You have to set a "0" before the months and days which are < 10. GetMonth() starts with 0, therefore (getMonth() + 1).

使用getDate(),getMonth()和getFullYear()。您必须在<10之前的月份和日期之前设置“0”.GetMonth()以0开头,因此(getMonth()+ 1)。

function getFormattedDate() {
    var date = new Date();
    var day = date.getDate() > 9 ? date.getDate() : "0" + date.getDate();
    var month = (date.getMonth() + 1) > 9 ? (date.getMonth() + 1) : "0" + (date.getMonth() + 1);
    var year = date.getFullYear();
    var formattedDate = day + "-" + month + "-" + year;
    return formattedDate;
}

console.log(getFormattedDate());

Demo

#1


0  

Hi this should do the trick

嗨,这应该做的伎俩

FORMAT: mm-dd-yyyy

function addZeroIfRequired(dayOrMonth) {
    return dayOrMonth > 9 ? dayOrMonth : "0"+dayOrMonth;
}

function getDate(dateString) {
   var date = dateString ? new Date(dateString) : new Date();
   return addZeroIfRequired((date.getUTCMonth()+1)) + "-" + 
          addZeroIfRequired(date.getDate())+  "-" + 
          date.getUTCFullYear();
}

console.log(getDate()); // 05-23-2015
console.log(getDate("Fri May 22 2015 13:32:25 GMT-0400")); 05-22-2015

NOTE: the +1 after the getUTCMonth().

注意:getUTCMonth()之后的+1。

JSFiddle. Open the console to see the result. https://jsfiddle.net/wt79yLo0/2/

的jsfiddle。打开控制台以查看结果。 https://jsfiddle.net/wt79yLo0/2/

ISO FORMAT: yyyy-mm-dd

ISO格式:yyyy-mm-dd

Just in case someone is interested in the opposite format, the code would be much nicer and neater:

为了防止有人对相反的格式感兴趣,代码会更好更整洁:

function getDate(dateString) {
   var date = dateString ? new Date(dateString) : new Date();
   return date.toISOString().substring(0, 10);
}

console.log(getDate());
console.log(getDate("Fri May 22 2015 13:32:25 GMT-0400"));

https://jsfiddle.net/wt79yLo0/

#2


0  

First I would recommend a very powerful library for JS called Moment.js which solves all this kind of problems.

首先,我会推荐一个非常强大的JS库,名为Moment.js,它解决了所有这些问题。

But if you only want a snippet, here is my proposal:

但如果你只想要一个片段,这是我的建议:

function twoDigits(num) { 
    return ("0" + num).substr(-2); 
}

function getFormattedDateDMY(date, separator) {
    var day = twoDigits(date.getDate());
    var month = twoDigits(date.getMonth());
    var year = date.getFullYear();
    return [day,month,year].join(separator);
}

function getFormattedDateMDY(date, separator) {
    var day = twoDigits(date.getDate());
    var month = twoDigits(date.getMonth());
    var year = date.getFullYear();
    return [month,day,year].join(separator);
}

console.log(getFormattedDateDMY(new Date(), "-"));  //23-04-2015
console.log(getFormattedDateMDY(new Date(), "-"));  //04-23-2015

#3


0  

With getDate(), getMonth() and getFullYear(). You have to set a "0" before the months and days which are < 10. GetMonth() starts with 0, therefore (getMonth() + 1).

使用getDate(),getMonth()和getFullYear()。您必须在<10之前的月份和日期之前设置“0”.GetMonth()以0开头,因此(getMonth()+ 1)。

function getFormattedDate() {
    var date = new Date();
    var day = date.getDate() > 9 ? date.getDate() : "0" + date.getDate();
    var month = (date.getMonth() + 1) > 9 ? (date.getMonth() + 1) : "0" + (date.getMonth() + 1);
    var year = date.getFullYear();
    var formattedDate = day + "-" + month + "-" + year;
    return formattedDate;
}

console.log(getFormattedDate());

Demo