如何在CodeIgniter中使用PHP显示表单字段？

I have select input in my form for manufacturers.

我已经为我的表格选择了制造商的输入。

<div class="form-group">
    <label for="manufacturer">Manufacturer</label>
    <select id="manufacturerSelect" name="manufacturer" class="form-control">
        <option disabled selected value> -- select an manufacturer -- </option>
        <?php foreach ($manufacturers as $manufacturers_item): ?>
            <option value="<?=$manufacturers_item['id'];?>" <?php echo set_select('manufacturer',$manufacturers_item['id'], ( !empty($manufacturer) && $manufacturer == $manufacturers_item['id'] ? TRUE : FALSE )); ?> ><?=$manufacturers_item['name'];?></option>
        <?php endforeach; ?>
         <option disabled>──────────</option>
        <option value="24" <?php echo set_select('manufacturer','24', ( !empty($manufacturer) && $manufacturer == '24' ? TRUE : FALSE )); ?> >Other</option>
    </select>
    <?php echo form_error('manufacturer'); ?><br />
</div>

If "other" (value == 24) is checked additional input is asked:

如果选中“其他”（值== 24），则会询问其他输入：

$('body').on('change', '#manufacturerSelect', function() { 
    if ($(this).val() == 24) {
        $("#otherManufacturerSelect").removeClass('hidden');
    } else {
        $("#otherManufacturerSelect").addClass('hidden')
    }
});

And HTML:

和HTML：

<div id="otherManufacturerSelect"  class="form-group">
    <label for="otherManufacturer" >What is it then?</label>
    <input type="text" name="otherManufacturer" class="form-control">
    <?php echo form_error('otherManufacturer'); ?><br />
</div>

CSS:

CSS：

.hidden {
    display: hidden;
}

Now if user picks "other" as manufacturer addition input is displayed. Form validation rule for otherManufacturer is added in server side if manufacturer == 24. The problem is that the other manufacturer input is displayed every time user get response from server. I could add class="hidden" by default to other manufacturer div but if the form validation doesnt run other manufacturer field will not be displayed again to user.

现在，如果用户选择“其他”作为制造商，则显示添加输入。如果制造商== 24，则在服务器端添加其他制造商的表单验证规则。问题是每次用户从服务器获得响应时都会显示其他制造商输入。我可以默认将class =“hidden”添加到其他制造商div，但如果表单验证没有运行，则其他制造商字段将不再显示给用户。

What I need is PHP IF condition inside:

我需要的是PHP IF条件里面：

<div id="otherManufacturerSelect" <?php if(/*???*/):?>class="hidden"<?php endif; ?> class="form-group">

class =“hidden”<？php endif; ？> class =“form-group”>

So that class="hidden" would be added only if manufacturer is not "other". but I cannt think of rigth condition.

因此，只有当制造商不是“其他”时，才会添加class =“hidden”。但我无法想到严峻的条件。

Any help would be appreciated!

任何帮助，将不胜感激！

EDIT

编辑

Controller:

控制器：

public function create()
{
    $this->load->helper(array('form', 'url'));
    $this->load->library('form_validation');

    $this->form_validation->set_rules('manufacturer', 'Manufacturer', 'required');
    if($this->input->post('manufacturer') == '24'){
        $this->form_validation->set_rules('otherManufacturer', 'Other manufacturer', 'required');
    }

    $data['manufacturers'] = $this->puzzles_model->getManufacturers();

    if ($this->form_validation->run() === FALSE)
    {
        $this->load->view('puzzles/create', $data);
    }
    else
    {
        /* do the upload, return upload errors or save in db*/
    }
}

1 个解决方案

#1

In your particular case this would fix the problem:

在您的特定情况下，这将解决问题：

<div id="otherManufacturerSelect" class="form-group <?php if(isset($manufacturer) && $manufacturer !== '24') { echo 'hidden'; } ?> ">
    <label for="otherManufacturer" >What is it then?</label>
    <input type="text" name="otherManufacturer" class="form-control">
    <?php echo form_error('otherManufacturer'); ?><br />
</div>

Then you can remove the JS snippet. The additional form will be hidden on server side (class="hidden" will be set).

然后你可以删除JS片段。附加表单将隐藏在服务器端（将设置class =“hidden”）。

I saw that you're using var $manufacturer in the same template. I can't see your controller and how you're passing variables but instead of $manufacturer you can also use $_GET['manufacturer'] or $_POST['manufacturer'] (depending on your form action method). Notice: $_GET['manufacturer'], $_POST['manufacturer'] and $_REQUEST['manufacturer'] is NOT sanitized input. When using $manufacturer I assume that it's sanitized in your controller.

我看到你在同一个模板中使用var $ manufacturer。我看不到你的控制器以及你如何传递变量但是你也可以使用$ _GET ['manufacturer']或$ _POST ['manufacturer']（取决于你的表单操作方法）而不是$ manufacturer。注意：$ _GET ['manufacturer']，$ _POST ['manufacturer']和$ _REQUEST ['manufacturer']未经过清理输入。使用$ manufacturer时，我认为它已在您的控制器中进行了清理。

#1