openCV实现将图像切成m*n块，供大家参考，具体内容如下
一、代码部分：
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
|
#include "stdafx.h"
#include <opencv2/core/core.hpp>
#include <opencv2/highgui/highgui.hpp>
#include <iostream>
#include <vector>
#include<string>
#include<sstream>
using namespace std;
using namespace cv;
//Cut an image into m*n patch
void Cut_img(Mat src_img, int m, int n, vector<Mat> ceil_img)
{
int t = m * n;
int height = src_img.rows;
int width = src_img.cols;
int ceil_height = height / m;
int ceil_width = width / n;
Mat roi_img;
//String concatenation
ostringstream oss;
string str, str1, str2;
Point p1, p2;
for (int i = 0; i<m; i++)
{
for (int j = 0; j<n; j++)
{
Rect rect(j*ceil_width, i*ceil_height, ceil_width, ceil_height);
src_img(rect).copyTo(roi_img);
ceil_img.push_back(roi_img);
oss << i;
str1 = oss.str();
oss.str("");
oss << j;
str2 = oss.str();
oss.str("");
str = "roi_img_" + str1 + "_" + str2;
imshow(str, roi_img);
IplImage *ipl_roi_img=&IplImage(roi_img);
//save processed img
char tmp[100]="\0";
sprintf(tmp,"..\\post_img\\71253_%d_%d.jpg",i,j);
cvSaveImage(tmp,ipl_roi_img);
}
}
}
int _tmain(int argc, _TCHAR* argv[])
{
char *img_name_path="..\\image\\71253.jpg";
Mat img = imread(img_name_path,1);
imshow("src_img", img);
waitKey(0);
int m = 2;
int n = 2;
vector<Mat> ceil_img ;
Cut_img(img, m, n, ceil_img);
cvWaitKey(0);
return 0;
}
|
二、程序运行结果：
（1）原图像：
（2）切割后图像：
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持服务器之家。
原文链接：https://blog.csdn.net/lindamtd/article/details/75194993