在jQuery中传递JSON数据到.getJSON ?

I am trying to pass a JSON object to .getJSON but I keep getting a bad request error. This is what I am trying:

我正在尝试将一个JSON对象传递给。getjson，但是我总是得到一个错误的请求。这就是我正在尝试的:

var data = {
    "SomeID": "18",
    "Utc": null,
    "Flags": "324"
};

$.getJSON("https://somewhere.com/AllGet?callback=?", JSON.stringify(data), function (result) {
    alert(result);
});

Currently to get it working, I have to do this, but I do not like how I have to manually construct the query string:

目前要让它工作，我必须这么做，但我不喜欢我必须手工构造查询字符串:

$.getJSON("https://somewhere.com/AllGet?SomeID=18&Utc=&Flags=324&callback=?", null, function (result) {
        alert(result);
    });

Anyone know how to make requests easier with JSON objects being passed in? I would appreciate any help or advise.

有谁知道如何通过传入的JSON对象简化请求吗?我希望得到任何帮助或建议。

7 个解决方案

#1

according to the site, this is valid:

根据该网站，这是有效的:

$.getJSON("test.js", { name: "John", time: "2pm" }, function(json) {
    alert("JSON Data: " + json.users[3].name);
    });

so try:

所以尝试:

var data = {
    SomeID: "18",
    Utc: null,
    Flags: "324"
};

$.getJSON("https://somewhere.com/AllGet?callback=?", data, function (result) {
    alert(result);
});

edit: http://api.jquery.com/jQuery.getJSON/

编辑:http://api.jquery.com/jQuery.getJSON/

#2

Dont use JSON.stringfy, just pass data as it is.

不要使用JSON。stringfy只传递数据。

$.getJSON("https://somewhere.com/AllGet?callback=?", data, function (result) {
    alert(result);
});

#3

When you provide data to a jQuery GET request, it expects an object, not a JSON string, for constructing the query string parameters. Try changing your original code to just this:

当您向jQuery GET请求提供数据时，它需要一个对象(而不是JSON字符串)来构造查询字符串参数。尝试将您的原始代码修改为以下内容:

$.getJSON("https://somewhere.com/AllGet?callback=?", data, function (result) {
    alert(result);
});

#4

You don't need to do JSON.stringfy, just pass the JSON object, jQuery will construct your URL parameter with that

不需要使用JSON。stringfy只传递JSON对象，jQuery将用它构造URL参数

$.getJSON("https://somewhere.com/AllGet?callback=?", data, function (result) {
    alert(result);
});

#5

why exactly do you need a callback? (Ow wait, jsonp) I'd try the following first:

为什么需要回调呢?(哦，等等，jsonp)我先试试下面的:

$.getJSON("https://somewhere.com/AllGet?callback=?", data, function(result) {
  alert(result);
});

somewhere in firebug and see if it returns what you expect. I'm not sure what a string as data does, but just giving an object works fine afaik.

在firebug的某个地方，看看它是否能返回您所期望的。我不确定字符串作为数据的功能是什么，但是仅仅给出一个对象就可以很好地工作。

#6

$.getJSON("https://somewhere.com/AllGet?callback=?", {SomeID:"18",Utc:null,Flags:"324"}, function (result) {
        alert(result);
    });

或

var data = {
    "SomeID": "18",
    "Utc": null,
    "Flags": "324"
};


$.getJSON("https://somewhere.com/AllGet?callback=?",
 {
SomeID:data.SomeID,
Utc:data.Utc,
Flags:data.Flags
},
 function (result) {
            alert(result);
        });

#7

I tried encoding the json and it worked.

我尝试编码json，它成功了。

Not sure how efficient or practical it is, sharing it just as a work around for above question.

不知道它有多高效，有多实用，分享它就像一个围绕上述问题的工作。

 $.getJSON("https://somewhere.com/AllGet?data="+encodeURI(JSON.stringify(data)), function (result) {
        alert(result);
 });

#1