I want to make 11 buttons specified below order with 2 for loops, it is a matrix but for 11 buttons.
我想在下面指定11个按钮,2个循环,它是一个矩阵,但是11个按钮。
for (int i = 1; i <= 2; i++) {
for (int k = 1; k <= 6; k++) {
j++;
NSString *key = [NSString stringWithFormat:@"Color%d",j];
UIColor *color = [dict objectForKey:key];
ColorBtn *colorBtn = [UIButton buttonWithType:UIButtonTypeCustom];
colorBtn.frame = CGRectMake(4+(startPointX*k), 320+(startPointY*i), 38, 37);
colorBtn.backgroundColor = color;
colorBtn.tag = j;
[colorBtn setImage:[UIImage imageNamed:@"image.png"] forState:UIControlStateNormal];
[colorBtn addTarget:self action:@selector(SetUIColor:) forControlEvents:UIControlEventTouchUpInside];
[self.view addSubview:colorBtn];
}
}
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2 个解决方案
#1
1
Simply add a few lines to your inner for loop towards the top:
只需在内部添加几行以循环到顶部:
...
j++;
// Add these lines
if (i == 2 && k == 6) {
continue;
}
// Add these lines
NSString *key = [NSString stringWithFormat:@"Color%d",j];
...
This will ensure that the final column in the second row is skipped.
这将确保跳过第二行中的最后一列。
Another alternative is to check the value of j - this would allow you to change the dimensions of your matrix while still ensuring only 11 entries are created in total:
另一种方法是检查j的值 - 这将允许您更改矩阵的尺寸,同时仍然确保总共只创建了11个条目:
...
j++;
// Add these lines
// I'm assuming that j is 1-based, not 0-based
if (j > 11) {
break;
}
// Add these lines
NSString *key = [NSString stringWithFormat:@"Color%d",j];
...
#2
0
for (int i = 1; i <= 2; i++) {
for(int i = 1; i <= 2; i ++){
for (int k = 1; k <= 6; k++) {
for(int k = 1; k <= 6; k ++){
j++; if(j<12) { //Your code for creating buttons.
J ++; if(j <12){//您创建按钮的代码。
}
} }
for j=0(at starting).
对于j = 0(在开始时)。
#1
1
Simply add a few lines to your inner for loop towards the top:
只需在内部添加几行以循环到顶部:
...
j++;
// Add these lines
if (i == 2 && k == 6) {
continue;
}
// Add these lines
NSString *key = [NSString stringWithFormat:@"Color%d",j];
...
This will ensure that the final column in the second row is skipped.
这将确保跳过第二行中的最后一列。
Another alternative is to check the value of j - this would allow you to change the dimensions of your matrix while still ensuring only 11 entries are created in total:
另一种方法是检查j的值 - 这将允许您更改矩阵的尺寸,同时仍然确保总共只创建了11个条目:
...
j++;
// Add these lines
// I'm assuming that j is 1-based, not 0-based
if (j > 11) {
break;
}
// Add these lines
NSString *key = [NSString stringWithFormat:@"Color%d",j];
...
#2
0
for (int i = 1; i <= 2; i++) {
for(int i = 1; i <= 2; i ++){
for (int k = 1; k <= 6; k++) {
for(int k = 1; k <= 6; k ++){
j++; if(j<12) { //Your code for creating buttons.
J ++; if(j <12){//您创建按钮的代码。
}
} }
for j=0(at starting).
对于j = 0(在开始时)。