尝试在PHP中回显输入文本时未定义的索引错误？

I am trying to echo the contents of an input field on enter. I have a text input field that I create here:

我试图在输入上回显输入字段的内容。我有一个我在这里创建的文本输入字段:

echo '<form id="changePassForm" action="" method="post" enctype="multipart/form-data">
  <div class="changePass">
    <div class="changePassBtn">Change Password</div>
    <input class = "passwordText" type="password" placeholder="Password" name="passwordText">
  </div>';

The field calls this javascript function correctly:

该字段正确调用此javascript函数:

$(".passwordText").keydown(function(event){
    if(event.keyCode == 13){

    $.ajax({
        url: "../php/passwordchange.php", // Url to which the request is send
        type: "POST",             // Type of request to be send, called as method
        data: new FormData(this), // Data sent to server, a set of key/value pairs (i.e. form fields and values)
        datatype: 'text',
        contentType: false,       // The content type used when sending data to the server.
        cache: false,             // To unable request pages to be cached
        processData:false,        // To send DOMDocument or non processed data file it is set to false
        success: function(data)   // A function to be called if request succeeds
        {
            console.log(data);

        }});    
     console.log("WORKS!!");   
    }
});

Which references password change.php here:

这里引用密码change.php:

<?php

session_start();
    echo "Hello world";

    $pass=$_POST['passwordText']; //name of input
    echo $pass;

/*$dbh = new PDO("mysql:host=localhost;dbname=sqlserver", 'username', 'password');
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

    $checkforpass = "SELECT password FROM sqlserver.accounts WHERE username='".$username."'";*/

?>

I'm not versed in PHP but Hello world is output to console. How can I output/store value of text field in $pass?

我不熟悉PHP,但Hello world输出到控制台。如何在$ pass中输出/存储文本字段的值?

3 个解决方案

#1

Untested, off the cuff:

未经测试,脱下袖口:

$(".passwordText").keydown(function(event){
    if(event.keyCode == 13){
      var pass = $('#changePassForm input').val();
    $.ajax({
        url: "../php/passwordchange.php", // Url to which the request is send
        type: "POST",             // Type of request to be send, called as method
        data: 'passwordText=' + pass, // Data sent to server, a set of key/value pairs (i.e. form fields and values)
        success: function(data)   // A function to be called if request succeeds
        {
            console.log(data);

        }});    
     console.log("WORKS!!");   
    }
});

---

Note also that it is dataType: not datatype:, and that dataType only affects returning data not data being sent to PHP

另请注意,它是dataType:not datatype:,并且该dataType仅影响返回数据而不影响发送给PHP的数据

So, get it working simply first (as above), then get fancy with $('#changePassForm').serialize() etc.

因此,首先让它工作(如上所述),然后使用$('#changePassForm')。serialize()等。

#2

Try as follows

尝试如下

$(".passwordText").keydown(function(event){
    if(event.keyCode == 13){
      var postData = $('#changePassForm').serializeArray();
    $.ajax({
        url: "../php/passwordchange.php", // Url to which the request is send
        type: "POST",             // Type of request to be send, called as method
        data: postData, // Data sent to server, a set of key/value pairs (i.e. form fields and values)
        datatype: 'text',
        contentType: false,       // The content type used when sending data to the server.
        cache: false,             // To unable request pages to be cached
        processData:false,        // To send DOMDocument or non processed data file it is set to false
        success: function(data)   // A function to be called if request succeeds
        {
            console.log(data);

        }});    
     console.log("WORKS!!");   
    }
});

#3

If you want to use FormData, you can see from the manual that the FormData object constructor takes an optional <form> element and you're using this, which refers to $(".passwordText"), which is a jQuery object. You can pass a form element by doing:

如果你想使用FormData,你可以从手册中看到FormData对象构造函数采用一个可选的

元素,而你正在使用它,它引用了$(“。passwordText”),这是一个jQuery对象。您可以通过执行以下操作传递表单元素:

var form = document.getElementById("changePassForm");
var fd = new FormData(form);

Putting this all together we would then have:

把这一切放在一起我们就会:

$(document).ready(function() {
  $(".passwordText").keydown(function(event){
    if(event.keyCode == 13){
      event.preventDefault();
      var form = document.getElementById("changePassForm");
      var fd = new FormData(form);

      $.ajax({
        url: "../php/passwordchange.php", // Url to which the request is send
        type: "POST",             // Type of request to be send, called as method
        data: fd, // Data sent to server, a set of key/value pairs (i.e. form fields and values)
        dataType: 'text',
        cache: false,             // To unable request pages to be cached
        processData:false,        // To send DOMDocument or non processed data file it is set to false
        success: function(data)   // A function to be called if request succeeds
        {
            console.log(data);

        }});    
       console.log("WORKS!!");   
    }
  });
});

As an alternative you can manually append any values you want to have sent in the ajax request like this:

作为替代方案,您可以手动附加要在ajax请求中发送的任何值,如下所示:

var fd = new FormData();
fd.append($(this).attr("name"), $(this).attr("value"));

---

Disclaimer:

With that said, the FormData interface is only available in IE >= 10, so if you are worried about cross browser compatibility you may want to consider simply using jQuery's serialize() method to send the data. As an added bonus, it's only 1 line of code.:

话虽如此,FormData接口仅在IE> = 10时可用,因此如果您担心跨浏览器兼容性,您可能需要考虑使用jQuery的serialize()方法来发送数据。作为额外的奖励,它只有一行代码:

data: $("#changePassForm").serialize()