Xcode6:使用Objective-C的IBDesignable和IBInspectable。

I have an Objective-C UI component that I'd like to make inspectable in Interface Builder with Xcode 6. Swift has the @IBDesignable and @IBInspectable declaration attributes. Are they available also in Objective-C? How are they used?

我有一个Objective-C UI组件，我想用Xcode 6在Interface Builder中进行检查。Swift具有@IBDesignable和@IBInspectable声明属性。在Objective-C中也有吗?他们是如何使用?

2 个解决方案

#1

The equivalents are IB_DESIGNABLE and IBInspectable—see the documentation for Objective C examples.

对应的是IB_DESIGNABLE和ibinspectable——查看Objective - C示例的文档。

Also, this year's WWDC video "What's New in Interface Builder" has its examples in Swift, but the presenter also mentions the Objective C equivalents in passing.

另外，今年的WWDC视频“界面构建器的新功能”在Swift中也有它的例子，但是演示者也提到了通过的Objective C。

#2

Code example:

代码示例:

#import <UIKit/UIKit.h>
IB_DESIGNABLE
@interface LOLView : UIView
@property (nonatomic) IBInspectable UIColor *someColor; 
@end

#1