This question already has an answer here:
这个问题已经有了答案:
- Splitting string into pair of characters in Ruby 2 answers
- 在Ruby 2中，将字符串分割成一对字符
I have the string "abigword" and I want to take the array ["ab", "ig", "wo", "rd"]. To generalize, given a string, I want to take the array of its constituent characters paired two-by-two.
我有一个字符串"abigword"我想取数组"ab" ig" wo" rd"为了推广，给定一个字符串，我想取它的组成字符的数组，成对的2乘2。
What is the most elegant Ruby way to do that?
最优雅的Ruby方法是什么?
2 个解决方案
#1
10
"abigword".scan(/../) # => ["ab", "ig", "wo", "rd"]
It can also handle odd number of chars if you want:
它也可以处理奇数字符，如果你想:
"abigwordf".scan(/..?/) # => ["ab", "ig", "wo", "rd", "f"]
#2
3
Two non-regexp versions:
两个non-regexp版本:
#1:
p "abigword".chars.each_slice(2).map(&:join) #=> ["ab", "ig", "wo", "rd"]
#2:
s, a = "abigword", []
a << s.slice!(0,2) until s.empty?
p a #=> ["ab", "ig", "wo", "rd"]
#1
10
"abigword".scan(/../) # => ["ab", "ig", "wo", "rd"]
It can also handle odd number of chars if you want:
它也可以处理奇数字符，如果你想:
"abigwordf".scan(/..?/) # => ["ab", "ig", "wo", "rd", "f"]
#2
3
Two non-regexp versions:
两个non-regexp版本:
#1:
p "abigword".chars.each_slice(2).map(&:join) #=> ["ab", "ig", "wo", "rd"]
#2:
s, a = "abigword", []
a << s.slice!(0,2) until s.empty?
p a #=> ["ab", "ig", "wo", "rd"]