原题:http://acm.hdu.edu.cn/showproblem.php?pid=1001
#include <stdio.h> int main(void)
{
int i,n,sum;
sum = ;
while(scanf("%d",&n)!=EOF)
{
sum=;
for (i=;i<=n;i++)
sum+=i;
printf("%d\n\n",sum);
}
return ;
}
Sum Problem
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 416900 Accepted Submission(s): 105068
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1
100
100
Sample Output
1
5050