题目:https://www.lydsy.com/JudgeOnline/problem.php?id=1911
相当明显的斜率优化,很好做;
注意slp里面要有(double),以免出现精度问题。
代码如下:
#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
typedef long long ll;
int const maxn=1e6+;
ll n,a,b,c,s[maxn],q[maxn],f[maxn];
ll y(int i){return f[i]+a*s[i]*s[i]-b*s[i];}
double slp(int i,int j){return (double)(y(j)-y(i))/(s[j]-s[i])//a;}//在这里/2/a
int main()
{
scanf("%lld%lld%lld%lld",&n,&a,&b,&c);
for(int i=;i<=n;i++)
scanf("%lld",&s[i]),s[i]+=s[i-];
int head=,tail=;
for(int i=;i<=n;i++)
{
while(head<tail&&slp(q[head],q[head+])<=s[i])head++;//则这里没有*2*a,否则需要区分a的正负
int j=q[head];
double tmp=s[i]-s[j];
f[i]=f[j]+a*tmp*tmp+b*tmp+c;
while(head<tail&&slp(q[tail-],q[tail])>slp(q[tail-],i))tail--;//
q[++tail]=i;
}
printf("%lld",f[n]);
return ;
}