fibonacci高精度加法

A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. 
F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) 
Your task is to take a number as input, and print that Fibonacci number. 

Input

Each line will contain an integers. Process to end of file. 

Output

For each case, output the result in a line.

Sample Input

100

Sample Output

4203968145672990846840663646

Note:
No generated Fibonacci number in excess of 2005 digits will be in the test data, ie. F(20) = 66526 has 5 digits.

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <string.h>
#include <malloc.h>
using namespace std;

void add(char* a,char* b,char* c)
{
    int i,j,k,max,min,n,temp;
    char *s,*pmax,*pmin;
    max=strlen(a);
    min=strlen(b);
    if (max<min)
    {
        temp=max;
        max=min;
        min=temp;
        pmax=b;
        pmin=a;
    }
    else
    {
        pmax=a;
        pmin=b;
    }
    s=(char*)malloc(sizeof(char)*(max+));
    s[]='';
    for (i=min-,j=max-,k=max; i>=; i--,j--,k--)
        s[k]=pmin[i]-''+pmax[j];
    for (; j>=; j--,k--)
        s[k]=pmax[j];
    for (i=max; i>=; i--)
        if (s[i]>'')
        {
            s[i]-=;
            s[i-]++;
        }
    if (s[]=='')
    {
        for (i=; i<=max; i++)
            c[i-]=s[i];
        c[i-]='\0';
    }
    else
    {
        for (i=; i<=max; i++)
            c[i]=s[i];
        c[i]='\0';
    }
    free(s);
}
char a[][];
int main(void)
{
    int i,n;
    for(i=;i<=;i++)
    strcpy(a[i],"");
    for(i=;i<;i++)
    {
        char x[],y[];
        add(a[i-],a[i-],x);
        add(a[i-],a[i-],y);
        add(x,y,a[i]);
    }
    while(cin>>n)
    {
        cout<<a[n]<<endl;
    }
    return ;
}