如何解析Objective C中的字符串

Can someone help me to extract int timestamp value from this string "/Date(1242597600000)/" in Objective C

有人可以帮我从Objective C中的字符串“/ Date(1242597600000)/”中提取int时间戳值

I would like to get 1242597600000.

我想得到1242597600000。

Thx

3 个解决方案

#1

One simple method:

一个简单的方法:

NSString *timestampString = @"\/Date(1242597600000)\/";
NSArray *components = [timestampString componentsSeparatedByString:@"("];
NSString *afterOpenBracket = [components objectAtIndex:1];
components = [afterOpenBracket componentsSeparatedByString:@")"];
NSString *numberString = [components objectAtIndex:0];
long timeStamp = [numberString longValue];

Alternatively if you know the string will always be the same length and format, you could use:

或者,如果您知道字符串将始终具有相同的长度和格式,您可以使用:

NSString *numberString = [timestampString substringWithRange:NSMakeRange(7,13)];

And another method:

另一种方法:

NSRange openBracket = [timestampString rangeOfString:@"("];
NSRange closeBracket = [timestampString rangeOfString:@")"];
NSRange numberRange = NSMakeRange(openBracket.location + 1, closeBracket.location - openBracket.location - 1);
NSString *numberString = [timestampString substringWithRange:numberRange];

#2

There's more than one way to do it. Here's a suggestion using an NSScanner;

这样做的方法不止一种。这是一个使用NSScanner的建议;

NSString *dateString = @"\/Date(1242597600000)\/";
NSScanner *dateScanner = [NSScanner scannerWithString:dateString];
NSInteger timestamp;

if (!([dateScanner scanInteger:&timestamp])) {
    // scanInteger returns NO if the extraction is unsuccessful
    NSLog(@"Unable to extract string");
}

// If no error, then timestamp now contains the extracted numbers.

#3

NSCharacterSet* nonDigits = [[NSCharacterSet decimalDigitCharacterSet] invertedSet];
NSString* digitString = [timestampString stringByTrimmingCharactersInSet:nonDigits];
return [digitString longValue];

#1