I build an API on laravel 4, and it returns json results. For the API, I created one folder. Now i created another external project for the web application and what I want is to access the API functions from the laravel app controller. To be more clear, how can i make external API request from laravel controller?
我在laravel 4上构建了一个API，它返回了json结果。对于API，我创建了一个文件夹。现在我为Web应用程序创建了另一个外部项目，我想要的是从laravel app控制器访问API函数。为了更清楚，我如何从laravel控制器发出外部API请求？
1 个解决方案
#1
37
You can use Guzzle:
你可以使用Guzzle：
Install it:
安装它：
composer require guzzle/guzzle ~3.0
Create a client setting the base URL:
创建设置基本URL的客户端：
$client = new \Guzzle\Service\Client('http://api.github.com/users/');
Get your response:
得到你的回复：
$response = $client->get("users/$username")->send();
And display it:
并显示它：
dd($response);
But if you are trying to follow the MVC pattern, you should not do this directly in your controller, so create a service class, you call from your controller or your repositories, to do this work for you.
但是如果你试图遵循MVC模式，你不应该直接在你的控制器中这样做，所以创建一个服务类，你从你的控制器或你的存储库调用，为你做这项工作。
#1
37
You can use Guzzle:
你可以使用Guzzle：
Install it:
安装它：
composer require guzzle/guzzle ~3.0
Create a client setting the base URL:
创建设置基本URL的客户端：
$client = new \Guzzle\Service\Client('http://api.github.com/users/');
Get your response:
得到你的回复：
$response = $client->get("users/$username")->send();
And display it:
并显示它：
dd($response);
But if you are trying to follow the MVC pattern, you should not do this directly in your controller, so create a service class, you call from your controller or your repositories, to do this work for you.
但是如果你试图遵循MVC模式，你不应该直接在你的控制器中这样做，所以创建一个服务类，你从你的控制器或你的存储库调用，为你做这项工作。