我们知道,Arrays.asList返回的是个ArrayList,但是为什么不能修改呢?而且,当我们这么操作的时候会抛UnsupportedOperationException异常
其实,原因有点隐蔽,当我们仔细看Arrays的源码会发现,Arrays自己实现了一个ArrayList,仅仅是名字和常用的那个相同而已,而它返回的数组对象可用的方法就在下边:
@SafeVarargs而,题目所说的remove、add方法此实现类就没有实现,再看它的父类(AbstractList<E>)中关于这两个方法的是实现:
public static <T> List<T> asList(T... a) {
return new ArrayList<>(a);
}
/**
* @serial include
*/
private static class ArrayList<E> extends AbstractList<E>
implements RandomAccess, java.io.Serializable
{
private static final long serialVersionUID = -2764017481108945198L;
private final E[] a;
ArrayList(E[] array) {
if (array==null)
throw new NullPointerException();
a = array;
}
public int size() {
return a.length;
}
public Object[] toArray() {
return a.clone();
}
public <T> T[] toArray(T[] a) {
int size = size();
if (a.length < size)
return Arrays.copyOf(this.a, size,
(Class<? extends T[]>) a.getClass());
System.arraycopy(this.a, 0, a, 0, size);
if (a.length > size)
a[size] = null;
return a;
}
public E get(int index) {
return a[index];
}
public E set(int index, E element) {
E oldValue = a[index];
a[index] = element;
return oldValue;
}
public int indexOf(Object o) {
if (o==null) {
for (int i=0; i<a.length; i++)
if (a[i]==null)
return i;
} else {
for (int i=0; i<a.length; i++)
if (o.equals(a[i]))
return i;
}
return -1;
}
public boolean contains(Object o) {
return indexOf(o) != -1;
}
}
/**
* {@inheritDoc}
*
* <p>This implementation always throws an
* {@code UnsupportedOperationException}.
*
* @throws UnsupportedOperationException {@inheritDoc}
* @throws ClassCastException {@inheritDoc}
* @throws NullPointerException {@inheritDoc}
* @throws IllegalArgumentException {@inheritDoc}
* @throws IndexOutOfBoundsException {@inheritDoc}
*/
public void add(int index, E element) {
throw new UnsupportedOperationException();
}
/**
* {@inheritDoc}
*
* <p>This implementation always throws an
* {@code UnsupportedOperationException}.
*
* @throws UnsupportedOperationException {@inheritDoc}
* @throws IndexOutOfBoundsException {@inheritDoc}
*/
public E remove(int index) {
throw new UnsupportedOperationException();
}
到这里,我们就已经很明朗的知道,Arrays.asList为什么不能移除、新增项了。
....................................................................
那么,我们该怎么办呢?
方法是有的,我们这么干:
String[] array = new String[]{"1","2","3","4"};这样就可以对 list 进行add、remove操作了。
List<String> list = new ArrayList<String>(Arrays.asList(array));