排序 via F#

时间:2022-01-22 15:53:06

冒泡排序:

let rec bsort_asc s =
let rec _bsort_asc = function
|x1::x2::xs when x1 > x2 ->
match _bsort_asc (x1::xs) with
|None -> Some(x2::x1::xs)
|Some xs2 -> Some(x2::xs2)
|x1::x2::xs ->
match _bsort_asc (x2::xs) with
|None -> None
|Some xs2 -> Some(x1::xs2)
|_ -> None
match _bsort_asc s with
|None -> s
|Some s2 -> bsort_asc s2

快速排序:

let rec quicksort =
function
[] -> []
|x::xs ->
quicksort [for i in xs do if i < x then yield i]@
x:: quicksort [for i in xs do if i >= x then yield i]

插入排序

let rec insert x = function
|[] -> [x]
|y::tl when x > y -> y::(insert x tl)
|l -> x::l
let rec insertion_sort alist =
match alist with
|[] -> []
|x::tl -> insert x (insertion_sort tl)

希尔排序

let shellsort f a =
let N = Array.length a - 1
let mutable width = 1
while width <= N do
width <- 3 * width + 1
width <- width / 3
while width >= 1 do
for i = width to N do
let v = a.[i]
let mutable j = i
while j >= width && (f a.[j - width] v) > 0 do
a.[j] <- a.[j-width]
j <- j - width
a.[j] <- v
let asc a b = (a - b)
let dec a b = (b - a)

直接选择排序

let rec ssort_asc alist =
match alist with
|[] -> []
|l ->
let minrest l =
let rec aux list min acc =
match list with
[] -> min, acc
|h::t ->
if h < min then aux t h (min::acc)
else aux t min (h::acc)
aux (List.tail l)(List.head l)[]
let (min, rest) = minrest l
min :: (ssort_asc rest)

堆排序

let swap (a:_ []) i j =
let temp = a.[i]
a.[i] <- a.[j]
a.[j] <- temp
let sift cmp (a:_ []) start count =
let rec loop root child =
if root * 2 + 1 < count then
let p = child < count - 1 && cmp a.[child] a.[child + 1] < 0
let child = if p then child + 1 else child
if cmp a.[root] a.[child] < 0 then
swap a root child
loop child (child * 2 + 1)
loop start (start * 2 + 1)
let heapsort cmp (a:_ []) =
let n = a.Length
for start = n/2 - 1 downto 0 do
sift cmp a start n
for term = n - 1 downto 1 do
swap a term 0
sift cmp a 0 term
let asc a b = (a - b)
let dec a b = (b - a)

归并排序

let split list =
let rec aux l acc1 acc2 =
match l with
|[] -> (acc1, acc2)
|[x] -> (x::acc1, acc2)
|x::y::tail -> aux tail (x::acc1) (y::acc2)
aux list [] []
let rec merge l1 l2 =
match (l1, l2) with
|(x, []) -> x
|([], y) -> y
|(x::tx, y::ty) ->
if x < y then x::merge tx l2
else y::merge l1 ty
let rec mergesort list =
match list with
|[] -> []
|[x] -> [x]
|_ ->
let (l1, l2) = split list
merge (mergesort l1) (mergesort l2)

基数排序

let radixSort (list:int array) : int array =
let largestInt = Array.maxBy abs list
let largestIntLen = if largestInt = 0 then 1 else (int(log10 (abs(largestInt |> double))) + 1)
for i = 0 to largestIntLen - 1 do
let mutable buckets = Array.create 19 (List.empty<int>)
for number in list do
let nthDigit nth number = int(abs(number) / int(10. ** (float(nth)))) % 10
let nth = nthDigit i number
if number < 0 then
buckets.[9 - nth] <- (List.append buckets.[9 - nth][number])
elif number = 0 then
buckets.[9 + nth] <- (List.append buckets.[9 + nth][number])
let mutable listIndex = 0
for bucket in buckets do
for num in bucket do
list.[listIndex] <- num
listIndex <- listIndex + 1
list