SQL语句实现横排？
有一个表：
BH GZLB JE
----------------------
001 A 100
001 B 150
001 C 110
002 A 99
002 B 180
002 C 150
003 A 160
003 B 170
003 C 130
用SQL语句如何将上面的表变成下面横向的排列方式呢。
BH A B C
-------------------
001 100 150 110
002 99 180 150
003 160 170 130
（GZLB 里面的字段是动态的，不是只有A,B,C 可能还有A,B,C,D,E...）
---------------------------------------------------------------
if exists(select name from sysobjects where name='tblA' and xtype='U')
drop table tblA
create table tblA(
BH char(3) not null,
GZLB varchar(3) not null,
JE int not null
)
go
insert tblA values('001', 'A', 100)
insert tblA values('001', 'B', 150)
insert tblA values('001', 'C', 110)
insert tblA values('002', 'A', 99)
insert tblA values('002', 'B', 180)
insert tblA values('002', 'C', 150)
insert tblA values('003', 'A', 160)
insert tblA values('003', 'B', 170)
insert tblA values('003', 'C', 130)
declare @sql varchar(600)
set @sql = 'select'
select distinct GZLB as 'GZLB' into tmp from tblA
select @sql = @sql +' max(case GZLB when '''+ GZLB +''' then JE else null end) as '''+ GZLB +''',' from tmp
set @sql = substring(@sql, 1, len(@sql)-1) +' from tblA group by BH'
exec(@sql)
---------------------------------------------------------------
用游标
declare @sqlstr varchar(2000)
declare @gzlb
select sqlstr='select bh'
declare cgzlb cursor for select gzlb from table
create table #a
(bh char(3))
open cgzlb
fetch next from cgzlb into @gzlb
while (fetch_status<>-1)
begin
exec('alter table #a add '+@gzlb +' char(1)')
exec('insert into #a (bh,'+@gzlb+' select bh,je from table where gzlb='''+@gzlb+'''')
select @sqlstr=@sqlstr+',sum(isnull('+@gzlb+'))'
fetch next from cgzlb into @gzlb
end
close cgzlb
deallocate cgzlb
select @sqlstr=@sqlstr+' from #a group by bh order by bh
execute(@sqlstr)
---------------------------------------------------------------
declare @sql varchar(6000)
set @sql = 'select '
select @sql = @sql +' sum(case GZLB when '''+ GZLB +''' then JE else null end) ['+ GZLB +'],' from (select distinct GZLB as GZLB from tblA) tmp
set @sql = substring(@sql, 1, len(@sql)-1) +' from tblA group by BH'
exec(@sql)