python 爬取猫眼电影top100数据

时间:2021-03-02 20:01:48

最近有爬虫相关的需求,所以上B站找了个视频(链接在文末)看了一下,做了一个小程序出来,大体上没有修改,只是在最后的存储上,由txt换成了excel。

  • 简要需求:爬虫爬取 猫眼电影TOP100榜单 数据
  • 使用语言:python
  • 工具:PyCharm
  • 涉及库:requests、re、openpyxl(高版本excel操作库)

实现代码

猫眼电影Robots

python 爬取猫眼电影top100数据

# -*- coding: utf-8 -*-
# @Author : yocichen
# @Email : yocichen@126.com
# @File : maoyan100.py
# @Software: PyCharm
# @Time : 2019
# @UpdateTime : 2020/4/26 import requests
from requests import RequestException
import re
import openpyxl
import traceback # Get page's html by requests module
def get_one_page(url):
try:
headers = {
'user-agent': 'Mozilla / 5.0(Windows NT 10.0; WOW64) AppleWebKit / 537.36(KHTML, likeGecko) Chrome / 53.0.2785.104Safari / 537.36Core / 1.53.4882.400QQBrowser / 9.7.13059.400'
}
# Sometimes, the proxies need to be replaced.
# You can get them by accessing https://www.kuaidaili.com/free/inha/
proxies = {
'http': '60.190.250.120:8080'
}
# use headers to avoid 403 Forbidden Error(reject spider)
response = requests.get(url, headers=headers, proxies=proxies)
if response.status_code == 200 :
return response.text
return None
except RequestException:
traceback.print_exc()
return None # Get useful info from html of a page by re module
def parse_one_page(html):
try:
pattern = re.compile('<dd>.*?board-index.*?>(\d+)<.*?<a.*?title="(.*?)"'
+'.*?data-src="(.*?)".*?</a>.*?star">[\\s]*(.*?)[\\n][\\s]*</p>.*?'
+'releasetime">(.*?)</p>.*?integer">(.*?)</i>.*?'
+'fraction">(.*?)</i>.*?</dd>', re.S)
items = re.findall(pattern, html)
return items
except Exception:
traceback.print_exc()
return [] # Main call function
def main(url):
page_html = get_one_page(url)
parse_res = parse_one_page(page_html)
return parse_res # Write the useful info in excel(*.xlsx file)
def write_excel_xlsx(items):
wb = openpyxl.Workbook()
ws = wb.active
rows = len(items)
cols = len(items[0])
# First, write col's title.
ws.cell(1, 1).value = '编号'
ws.cell(1, 2).value = '片名'
ws.cell(1, 3).value = '宣传图片'
ws.cell(1, 4).value = '主演'
ws.cell(1, 5).value = '上映时间'
ws.cell(1, 6).value = '评分'
# Write film's info
for i in range(0, rows):
for j in range(0, cols):
if j != 5:
ws.cell(i+2, j+1).value = items[i][j]
else:
ws.cell(i+2, j+1).value = items[i][j]+items[i][j+1]
break
# Save the work book as *.xlsx
wb.save('maoyan_top100.xlsx') if __name__ == '__main__':
print('spider working...')
res = []
url = 'https://maoyan.com/board/4?'
for i in range(0, 10):
if i == 0:
res = main(url)
else:
newUrl = url+'offset='+str(i*10)
res.extend(main(newUrl))
print('writing into excel...')
write_excel_xlsx(res)
print('work done!\nNote: the data is in the current directory.')

更新效果图:

python 爬取猫眼电影top100数据

后记

入门了一点后发现,如果使用正则表达式和requests库来实行进行数据爬取的话,分析HTML页面结构和正则表达式的构造是关键,剩下的工作不过是替换url罢了。

你可能需要的 GitHub 传送门


补充一个分析HTML构造正则的例子

猫眼经典科幻按照评价排序

审查元素我们会发现每一项都是<dd>****</dd>格式

python 爬取猫眼电影top100数据

我想要获取电影名称和评分,先拿出HTML代码看一看

python 爬取猫眼电影top100数据

试着构造正则

'.*?<dd>.*?movie-item-title.*?title="(.*?)">.*?integer">(.*?)<.*?fraction">(.*?)<.*?</dd>' (随手写的,未经验证)


参考资料

【B站视频 2018年最新Python3.6网络爬虫实战】https://www.bilibili.com/video/av19057145/?p=14

【猫眼电影robots】https://maoyan.com/robots.txt (最好爬之前去看一下,那些可爬那些不允许爬)