POJ 2299 Ultra-QuickSort【树状数组 ,逆序数】
题意:给出一组数,然后求它的逆序数先把这组数离散化,大概就是编上号的意思---然后利用树状数组求出每个数前面有多少个数比它小,再通过这个数的位置,就可以求出前面有多少个数比它大了这一篇讲得很详细http://www.cnblogs.com/shenshuyang/archive/2012/07/14...
POJ2299 Ultra-QuickSort
DescriptionIn this problem, you have to analyze a particular sorting algorithm. The algorithm processes a sequence of n distinct integers by swapping ...
UVa 10810 - Ultra-QuickSort
题目大意:给出一个数列,每次交换相邻数字,求排成递增序的最少交换次数。分析:求逆序数,合并排序#include<cstdio>#include<cstring>#include<iostream>#define maxn 5000010using namespac...
POJ 2299 Ultra-QuickSort (求序列的逆序对数)
题意:废话了一大堆就是要你去求一个序列冒泡排序所需的交换的次数。 思路:实际上是要你去求一个序列的逆序队数 看案例: 9 1 0 5 49后面比它小的的数有4个 1后面有1个 0后面没有 5后面1个 4后面没有 所以结果为4+1+0+1+0=6 所以逆序对的定义如果不清楚可以自己总结了 这道题说...
Ultra-QuickSort (求逆序数+离散化处理)、Cows、Stars【树状数组】
一、Ultra-QuickSort(树状数组求逆序数)题目链接(点击)Ultra-QuickSortTime Limit: 7000MS Memory Limit: 65536KTotal Submissions: 73943 Accepted: 27692DescriptionIn this pr...
POJ 2299 Ultra-QuickSort(线段树入门)
Ultra-QuickSortTime Limit: 7000MS Memory Limit: 65536KDescriptionIn this problem, you have to analyze a particular sorting algorithm. The algorithm...
线段树——Ultra-QuickSort
题目网址:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=109331#problem/ADescriptionIn this problem, you have to analyze a particular sorting algori...
POJ 2299 Ultra-QuickSort
离散化+树状数组求逆序数Ultra-QuickSortTime Limit: 7000MSMemory Limit: 65536KTotal Submissions: 35024Accepted: 12608DescriptionIn this problem, you have to analyz...
Ultra-QuickSort (poj 2002)
DescriptionIn this problem, you have to analyze a particular sorting algorithm. The algorithm processes a sequence of n distinct integers by swapping ...
Ultra-QuickSort poj2299 (归并排序 求逆序数对)
Ultra-QuickSort Time Limit: 7000MS Memory Limit: 65536K Total Submissions: 57649 Accepted: 21298 Description In this pr...
Ultra-QuickSort 分类: POJ 排序 2015-08-03 15:39 2人阅读 评论(0) 收藏
Ultra-QuickSortTime Limit: 7000MS Memory Limit: 65536KTotal Submissions: 48111 Accepted: 17549DescriptionIn this problem, you have to analyze a partic...