Really Big Numbers CodeForces - 817C （数学规律+二分）
C. Really Big Numberstime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard outputIvan likes to learn differen...
CF 55D Beautiful numbers （数位DP）
题意： 如果一个正整数能被其所有位上的数字整除，则称其为Beautiful number，问区间[L,R]共有多少个Beautiful number？（1<=L<=R<=9*1018） 思路： 数字很大，不能暴力。但是想要知道一个数是否为Beautiful number...
CodeForces - 55D Beautiful numbers （数位DP）
Volodya is an odd boy and his taste is strange as well. It seems to him that a positive integer number is beautiful if and only if it is divisible by ...
POJ 3252 Round Numbers 数位dp（入门
题目链接：点击打开链接 题意： 给定一个区间，求区间内有多少个合法数（当这个数的二进制中0的个数>=1的个数称为合法数 二进制无前导0） 思路： cnt[i]表示二进制长度为i位（即最高位为1，其他位任意）时的合法数个数。 sum[i] 就是二进制长度<=i位的合法数个数。 然后从最高位...
SPOJ Balanced Numbers （数位DP+3进制状压）【模板】
BALNUM - Balanced Numbers no tags Balanced numbers have been used by mathematicians for centuries. A positive integer is considered a balanced numbe...
Educational Codeforces Round 8（D. Magic Numbers（数位DP））
题目链接：点击打开链接 题意：给一个m一个d， 一个字符串a和b， 问在[a,b]范围内， 有多少个可以整除m的魔法数， 魔法数的定义是， 偶数位上都是d， 奇数位上都不是d。 思路：据说是典型的数位DP， 以前没做过数位DP， 感觉和DP差不多？ 用d[i][j][p]表示当前到了第i位， 余数为...
POJ 3252 Round Numbers (数位DP)
题意：求区间内一个数二进制位1的数量大于等于0的数的个数。 析：dp[i][j][k] 表示前 i 位，长度为 j 的，1的数量是 k。注意前导0. 代码如下： #pragma comment(linker, "/STACK:1024000000,1024000000")#include <...
【CF ECR8-D】Magic Numbers（数位dp）
【CF ECR8-D】Magic Numbers（数位dp） D. Magic Numbers time limit per test:2 seconds ...
CF GYM 100703G Game of numbers
题意：给n个数，一开始基数为0，用这n个数依次对基数做加法或减法，使基数不超过k且不小于0，输出最远能运算到的数字个数，输出策略。解法：dp。dp[i][j]表示做完第i个数字的运算后结果为j的可能性，可能为1，不可能为0，于是得到状态转移方程dp[i][j] = dp[i - 1][j - a[i...
[LeetCode] Sum Root to Leaf Numbers 求根到叶节点数字之和
Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.An example is the root-to-leaf path 1->2->3...
A sequence of numbers （入门题-数学）
A sequence of numbers ...
浙江大学zoj 2001 Adding Reversed Numbers
#include<stdio.h>int reverse(int num){ int ans=0; while(num>0) { ans=ans*10+num%10; num=num/10; } return ans;}...
LeetCode902. Numbers At Most N Given Digit Set
题目：We have a sorted set of digits D, a non-empty subset of {'1','2','3','4','5','6','7','8','9'}. (Note that '0' is not included.)Now, we write numbe...
Identify Smith Numbers
Link:https://www.hackerrank.com/challenges/identify-smith-numbers def sum_digits(n): return sum(int(x) for x in str(n)) def prime_factors(n): ...
Store 7 Randomly generated numbers & names in an array Java
I'm not sure at all how to go about this, but I want to generate 1000 randomly generated 7 digit numbers, and 5 letter names. The names could be like ...
Codeforces899C-Dividing the numbers
C. Dividing the numbers time limit per test 1 second memory limit per test 256 megabytes input standard input output standard...
【SQL】180. Consecutive Numbers
Write a SQL query to find all numbers that appear at least three times consecutively.+----+-----+| Id | Num |+----+-----+| 1 | 1 || 2 | 1 || 3 ...
hdu 5505（GT and numbers）
题意：给你a和b，a每次和它的因子相乘得到一个新的a，求多少次后可以得到b。输入样例31 11 22 4输出样例0-11思路：每次找出a和b/a的最大公约数(即当前a想得到b能乘的最大数)，再进行判断。第一次直接暴力搞，超时了，发现题意理解错了 T_T。用unsign按着题意做即可。#include...
自测-4 Have Fun with Numbers（20 分）
Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 2469135...
00-自测4. Have Fun with Numbers (20)
00-自测4. Have Fun with Numbers (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 8000 B ...