Speech Module
1 FIRST_TEN = ["one", "two", "three", "four", "five", "six", "seven",
2 "eight", "nine"]
3 SECOND_TEN = ["ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen",
4 "sixteen", "seventeen", "eighteen", "nineteen"]
5 OTHER_TENS = ["twenty", "thirty", "forty", "fifty", "sixty", "seventy",
6 "eighty", "ninety"]
7 HUNDRED = "hundred"
8
9
10 def checkio(number):
11 spoken = []
12
13 hundred_bit = number / 100
14
15 if hundred_bit > 0:
16 spoken.append(FIRST_TEN[hundred_bit - 1])
17 spoken.append(HUNDRED)
18
19 remain = number % 100
20
21 if remain >= 10 and remain <= 19:
22 spoken.append(SECOND_TEN[remain % 10])
23 else:
24 decade = remain / 10
25 if decade > 0:
26 spoken.append(OTHER_TENS[decade - 2])
27
28 unit = remain % 10
29 if unit > 0:
30 spoken.append(FIRST_TEN[unit - 1])
31
32 return ' '.join(spoken)
python有个divmod函数, 即可返回商又可返回余数h, number = divmod(number, 100)
可以如此构造字符串 final_string = "%s%s%s" % (hundred_s, decade_s, unit_s)
使用strip去除字符,lstrip, rstrip; rstrip()去除右边空格