URAL 2056 Scholarship 水题

时间：2022-03-03 23:01:21

Scholarship
Time Limit: 20 Sec

Memory Limit: 256 MB

题目连接

http://acm.hust.edu.cn/vjudge/contest/view.action?cid=86686#problem/D

Description

At last the first term at the University came to its finish. Android Vasya has already passed all the exams and wants to know if he gets a scholarship. There is the following practice of giving scholarship to students at the University:
  • if a student has got satisfactory marks, the scholarship is not given,
  • if a student has passed through the examination period with only excellent marks, he gets a personal scholarship,
  • if a student doesn’t get a personal scholarship and his average mark is not less than 4.5, he gets a high scholarship,
  • if a student gets neither high nor personal scholarship and doesn’t have satisfactory marks, he gets a common scholarship.
A satisfactory mark corresponds to value 3, a good mark corresponds to value 4, and an excellent mark corresponds to value 5. An average mark for a student is the average value of all the marks this student got in his exams. Help Vasya find out which scholarship he gets.

Input

The first line contains an integer n that is the number of exams (1 ≤ n ≤ 10). In the i-th of the next n lines there is an integer mi that is value of Vasya’s mark in i-th exam (3 ≤ mi ≤ 5).

Output

If Vasya doesn’t get any scholarship output “None”. If he gets a common scholarship output “Common”, if he gets a high scholarship output “High”, if he gets a personal one output “Named”.

Sample Input

3
5
5
4

Sample Output

High

HINT

题意

给n门课，如果有一门为3分，那就没有奖学金，如果所有都是5分，那就单人奖学金，如果平均分超过4.5，就High奖学金，其他就普通奖学金

题解：

水题，读完题就A了……

代码：

#include <cstdio>

#include <cmath>

#include <cstring>

#include <ctime>

#include <iostream>

#include <algorithm>

#include <set>

#include <vector>

#include <sstream>

#include <queue>

#include <typeinfo>

#include <fstream>

#include <map>

#include <stack>

typedef long long ll;

using namespace std;

//freopen("D.in","r",stdin);

//freopen("D.out","w",stdout);

#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)

#define test freopen("test.txt","r",stdin)

#define maxn 20001

#define mod 1000000007

#define eps 1e-9

const int inf=0x3f3f3f3f;

const ll infll = 0x3f3f3f3f3f3f3f3fLL;

inline ll read()

{

    ll x=,f=;char ch=getchar();

    while(ch<''||ch>''){if(ch=='-')f=-;ch=getchar();}

    while(ch>=''&&ch<=''){x=x*+ch-'';ch=getchar();}

    return x*f;

}

//**************************************************************************************

int a[];

int main()

{

    int n=read();

    int flag=;

    int sum=;

    for(int i=;i<n;i++)

    {

        cin>>a[i];

        if(a[i]==)

            flag=;

        sum+=a[i];

    }

    if(flag)

    {

        cout<<"None"<<endl;

    }

    else if(sum==*n)

    {

        cout<<"Named"<<endl;

    }

    else if(sum>=4.5*(double)n)

    {

        cout<<"High"<<endl;

    }

    else

        cout<<"Common"<<endl;

}

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