这是一道意想不到的规律题。。。。。。。。。。。。或许是我比较菜，找不到把。
Description
Farmer John commanded his cows to search for different sets of numbers that sum to a given number. The cows use only numbers that are an integer power of 2. Here are the possible sets of numbers that sum to 7:
1) 1+1+1+1+1+1+1
2) 1+1+1+1+1+2
3) 1+1+1+2+2
4) 1+1+1+4
5) 1+2+2+2
6) 1+2+4
Help FJ count all possible representations for a given integer N (1 <= N <= 1,000,000).
Input
A single line with a single integer, N.
Output
The number of ways to represent N as the indicated sum. Due to the potential huge size of this number, print only last 9 digits (in base 10 representation).
Sample Input
7
Sample Output
6 规律是：1 2 2 4 4 6 6 10 10 14 14 20 20 26 26 36，，，由这里不难可以看出，如果是奇数位，则于他前一位相当。。。重点是偶数位，d[i]=d[i-1]+d[i/2],这规律真的是。。。。
AC代码：
#define MOD 10000000000
#define MAX 20000
#include<stdio.h>
int d[MAX];
int main()
{
int n;
scanf("%d",&n);
d[]=;
d[]=;
for(int i= ;i<=n ;i++)
if(i & )
d[i]=d[i-]%MOD;
else
d[i]=(d[i-]+d[i/])%MOD;
printf("%d\n",d[n]);
return ;
}