(easy)LeetCode 205.Isomorphic Strings (*)

时间:2021-09-29 14:40:00

Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given "egg""add", return true.

Given "foo""bar", return false.

Given "paper""title", return true.

Note:
You may assume both s and t have the same length.

解法:

代码如下:

public class Solution {
public boolean isIsomorphic(String s, String t) {
int []m1 = new int[256];
int []m2 = new int[256];
int len = s.length();
for (int i = 0; i < len; ++i) {
int m=s.charAt(i);
int n=t.charAt(i);
if(m1[m]!=m2[n])
return false;
m1[m] = i + 1;
m2[n] = i + 1;
}
return true;
}
}

运行结果:

 (easy)LeetCode  205.Isomorphic Strings (*)