如何从数据库中回显具有特定ID的行

So first off my database table is set up like this:

所以首先我的数据库表设置如下:

id | userid | amount | date | status

1 | 10 | 25.00 | 2017-09-12 | None

and I want to to echo out all the rows that include userid 10 into a html table. I have tried this:

我想将包含userid 10的所有行回显到html表中。我试过这个:

<?php
$id = $_GET['id'];
$userinfo= $mysqli->query("SELECT * FROM invoices WHERE userid = $id");
$row = mysql_fetch_array($userinfo) or die();

echo '<table>';
while($row = mysql_fetch_array($query)){
  echo '<tr>
  <td><font size="2" face="Lucida Sans Unicode" color=#EBEBEB>' .$row['id'].'</td>
  <td><font size="2" face="Lucida Sans Unicode" color=#EBEBEB>' .$row['amount'].'</td>
  <td><font size="2" face="Lucida Sans Unicode" color=#EBEBEB>' .$row['date'].'</td>
  <td><font size="2" face="Lucida Sans Unicode" color=#EBEBEB>' .$row['status'].'</td>
        </tr>';
}
echo '</table>';
?>

and nothing shows up.

没有任何表现。

3 个解决方案

#1

Use below code:

使用以下代码:

1 . use $userinfo instead of $query while($row = mysql_fetch_array($query))

1。使用$ userinfo而不是$ query while($ row = mysql_fetch_array($ query))

2 . Change $mysqli->query to mysqli_query.

2。将$ mysqli-> query更改为mysqli_query。

3 . Use mysqli instead of mysql.

3。使用mysqli而不是mysql。

<?php
$id = $_GET['id'];

//mysqli_connect("host","username","password","dbname") 
$conn=mysqli_connect("localhost","root","","dbname");
$sql="SELECT * FROM invoices WHERE userid = '.$id.'";
$result=mysqli_query($conn,$sql);

echo '<table>';
while($row = mysqli_fetch_array($result)){
  echo '<tr>
  <td>' .$row['id'].'</td>
  <td>' .$row['amount'].'</td>
  <td>' .$row['date'].'</td>
  <td>' .$row['status'].'</td>
        </tr>';
}
echo '</table>';
?>

#2

you mixing mysqli with mysql and object oriented style with Procedural

你使用Procedural将mysqli与mysql和面向对象的样式混合在一起

use object oriented as below

使用面向对象如下

<?php
$id = $_GET['id'];
$userinfo= $mysqli->query("SELECT * FROM invoices WHERE userid = $id");  
echo '<table>';

while($row = $userinfo->fetch_assoc()){
  echo '<tr>
  <td><font size="2" face="Lucida Sans Unicode" color=#EBEBEB>' .$row['id'].'</td>
  <td><font size="2" face="Lucida Sans Unicode" color=#EBEBEB>' .$row['amount'].'</td>
  <td><font size="2" face="Lucida Sans Unicode" color=#EBEBEB>' .$row['date'].'</td>
  <td><font size="2" face="Lucida Sans Unicode" color=#EBEBEB>' .$row['status'].'</td>
        </tr>';
}
echo '</table>';
?>

#3

Try this instead:

试试这个:

<?php
   $id = $_GET['id'];
   $mysqli = new \mysqli('localhost', 'username', 'password', 'database');
   $userinfo= $mysqli->query("SELECT id, amount, date, status FROM invoices WHERE userid = $id");

  echo '<table>';
  if ($userinfo->num_rows > 0) {
     while($row = $userinfo->fetch_assoc()) {
        echo '<tr>
           <td><font size="2" face="Lucida Sans Unicode" color=#EBEBEB>' .$row['id'].'</td>
           <td><font size="2" face="Lucida Sans Unicode" color=#EBEBEB>' .$row['amount'].'</td>
           <td><font size="2" face="Lucida Sans Unicode" color=#EBEBEB>' .$row['date'].'</td>
           <td><font size="2" face="Lucida Sans Unicode" color=#EBEBEB>' .$row['status'].'</td>
        </tr>';
     }
  }
  else {
     echo "0 rows returned";
  }
  echo '</table>';
?>

Also just me being annoying but don't use * in your select statement. Always list the fields even if you want every single one. You should also be using prepared statements.

另外我只是烦恼但不要在你的select语句中使用*。即使您想要每个字段,也要始终列出字段。您还应该使用预准备语句。

#1