如何在匹配具有泛型参数类型的多个函数定义中“GetMethod”？

I need to invoke a method on a class using reflection. The class contains two overloads for the same function:

我需要使用反射调用类的方法。该类包含两个相同函数的重载：

    string GenerateOutput<TModel>(TModel model);
    string GenerateOutput<TModel>(TModel model, string templateName);

I'm getting the method like so:

我得到的方法是这样的：

    Type type = typeof(MySolution.MyType);
    MethodInfo method = typeof(MyClass).GetMethod("GenerateOutput", new Type[] {type ,typeof(string)});
    MethodInfo generic = method.MakeGenericMethod(type);

The method is not fetched (method = null), I guess because the first method parameter is a generic type. How should this be handled?

我没有获取该方法（method = null），因为第一个方法参数是泛型类型。应如何处理？

2 个解决方案

#1

There are two possible issues - finding a method if it is non-public (the example shows non-public), and handling the generics.

有两个可能的问题 - 找到一个方法，如果它是非公开的（示例显示非公开的），并处理泛型。

IMO, this is the easiest option here:

IMO，这是最简单的选择：

MethodInfo generic = typeof(MyClass).GetMethods(
        BindingFlags.Public | BindingFlags.NonPublic | BindingFlags.Instance)
    .Single(x => x.Name == "GenerateOutput" && x.GetParameters().Length == 2)
    .MakeGenericMethod(type);

You could make the Single clause more restrictive if it is ambiguous.

如果不明确，您可以使Single子句更具限制性。

#2

In .NET, when working with generics and reflection, you need to provide how many generic parameters has a class or method like so:

在.NET中，当使用泛型和反射时，您需要提供有多少通用参数的类或方法，如下所示：

"NameOfMember`N"

Where "N" is generic parameters' count.

其中“N”是通用参数的计数。

#1