如何在mongodb中减去两个日期时间?

I have used aggregate function.

我用了聚合函数。

db.checkins.aggregate([
       {$match: {checkinType: "Beacon",
               "associationIds.organizationId":"af39bc69-1938-4149",
               "checkinData.time": {"$gte": new Date("2018-01-18T18:30:00.000Z"), 
                                   "$lt": new Date("2018-01-19T18:30:00.000Z")}
                }
        },
       {"$sort":{"checkinData.time":-1}},
       {$group: {"_id":
                    {"orgId":"$asst.organizationId", "userId":"$asst.userId"},
                    "lastSeen":{"$first":"$checkinData.time"},
                   "firstSeen":{"$last":"$checkinData.time"},
               }
       }, 
      {"$project":{"_id":1,"lastSeen":1, "firstSeen":1, 
                  totalHourSpent:{$subtract: ["$lastSeen","$firstSeen"]}}}, 
  ])

When I performed this Query mongo return totalHourSpent in milisecond which is given below.

当我执行这个查询时，mongo返回以毫秒为单位的total hours，如下所示。

{
  "_id" : {
        "orgId" : "af39bc69-1938-4149-b9f7-f101fd9baf73",
        "userId" : "34adb4a0-0012-11e7-bf32-cf79d6b423e9"
  },
 "lastSeen" : ISODate("2018-01-19T18:49:52.242+05:30"),
 "firstSeen" : ISODate("2018-01-19T10:08:21.026+05:30"),
 "totalHourSpent" : NumberLong("31291216")
},
{
  "_id" : {
       "orgId" : "af39bc69-1938-4149-b9f7-f101fd9baf73",
       "userId" : "679416b0-3f88-11e7-8d27-77235eb1ba9b"
   },
   "lastSeen" : ISODate("2018-01-19T20:51:30.946+05:30"),
   "firstSeen" : ISODate("2018-01-19T11:07:44.256+05:30"),
   "totalHourSpent" : NumberLong("35026690")
 },

How to calculate totalHourSpent in hour. Thanks in advance.

如何计算小时数。提前谢谢。

1 个解决方案

#1

The returned mills can be converted to hour by dividing with 1000*60*60 (3600000)

用1000*60*60(3600000)除以回收的磨粉机，可换算成小时

totalHourSpent:{$divide : [{$subtract: ["$lastSeen","$firstSeen"]}, 360000]}

ie

即

35026690÷3600000=9.72963611111111 hours