在Solaris上使用awk / nawk将标准时间戳转换为纪元格式

I need to convert some timestamp on Solaris to epoch format without any GNU installed.

我需要在没有安装任何GNU的情况下将Solaris上的某个时间戳转换为epoch格式。

I gave it a try with below code. However, sometime the return value has 1-2 days deviated from the correct value

我用下面的代码试了一下。但是，有时返回值有1-2天偏离正确的值

echo "Mar 20 20:09" | nawk -v FS="[: ]+" 'BEGIN {
    month_array["Jan"]="01";
    month_array["Feb"]="02";
    month_array["Mar"]="03";
    month_array["Apr"]="04";
    month_array["May"]="05";
    month_array["Jun"]="06";
    month_array["Jul"]="07";
    month_array["Aug"]="08";
    month_array["Sep"]="09";
    month_array["Oct"]="10";
    month_array["Nov"]="11";
    month_array["Dec"]="12";
}
{
    year=2016;
    month=month_array[$1];
    day=$2; hour=$3; minute=$4;
    if (month > 2) {
        month=month+1;
    } else {
        month=month+13; year=year-1;
    }

    day=(year*365)+(year/4)-(year/100)+(year/400)+(month*306001/10000)+day;
    days_since_epoch=day-719591;
    seconds_since_epoch=(days_since_epoch*86400)+(hour*3600)+(minute*60);
    printf "%d\n", seconds_since_epoch;
}'
1458677340

bash-3.2$ ctime 1458677340
Tue Mar 22 20:09:00 2016

Thanks so much

非常感谢

1 个解决方案

#1

Assuming all month have 30.6 days is obviously doomed.

假设整个月都有30.6天显然注定要失败。

Here are two ways to do what you want to achieve under Solaris.

以下是两种在Solaris下实现您想要实现的方法。

Using touch and truss (for the fun):

使用触摸和桁架（为了好玩）：

$ touch -t "03202009" file
$ truss -f -v 'lstat,lstat64' ls -d file 2>&1 | nawk '/mt =/ {printf "%d\n",$10}'
1458504540
$ ctime 1458504540
2016/03/20, 20:09:00

Using perl:

使用perl：

$ touch -t "03202009" file
$ perl -sle '@stat=stat($filename); print "$stat[8]"' -- -filename=file
1458504540

#1