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- Difference between matches() and find() in Java Regex 5 answers
Java Regex 5答案中matches()和find()之间的区别
Desired output : Java 1 8 true Output produced by this code Java 1 8 false what should be done to return true value ? the pattern of the input is [string] [dot][digit][dot][digit].
期望的输出:Java 1 8 true此代码生成的输出Java 1 8 false应该做什么来返回真值?输入的模式是[string] [dot] [digit] [dot] [digit]。
String st=java 1.8;
String regex="[\\s\\.]";
Pattern p=Pattern.compile(regex);
String []s2=p.split(st);
for(String a:s2)
System.out.println(a);
System.out.println(p.matches(st,regex));
} }
1 个解决方案
#1
1
You are splitting the string - thus it searches for a portion on your string for that regex.
您正在拆分字符串 - 因此它会在字符串中搜索该正则表达式的一部分。
When you use matches (which is static and the arguments are in reverse order), you are matching against the entire string.
当您使用匹配项(它是静态的并且参数的顺序相反)时,您将匹配整个字符串。
So for example:
例如:
System.out.println(Pattern.matches(regex, st));
where regex would change to ".+[\\s\\.].+" would print true.
正则表达式将更改为“。+ [\\ s \\。]。+”将打印为true。
#1
1
You are splitting the string - thus it searches for a portion on your string for that regex.
您正在拆分字符串 - 因此它会在字符串中搜索该正则表达式的一部分。
When you use matches (which is static and the arguments are in reverse order), you are matching against the entire string.
当您使用匹配项(它是静态的并且参数的顺序相反)时,您将匹配整个字符串。
So for example:
例如:
System.out.println(Pattern.matches(regex, st));
where regex would change to ".+[\\s\\.].+" would print true.
正则表达式将更改为“。+ [\\ s \\。]。+”将打印为true。