I have two arrays
我有两个数组
a = [1, 2, 3, 4, 5]
b = [2, 4, 6]
I would like to merge the two arrays, then remove the values that is the same with other array. The result should be:
我想合并这两个数组，然后删除与其他数组相同的值。结果应该是:
c = [1, 3, 5, 6]
I've tried subtracting the two array and the result is [1, 3, 5]. I also want to get the values from second array which has not duplicate from the first array..
我试着减去这两个数组，结果是[1,3,5]。我还想从第二个数组中获取值，第二个数组与第一个数组中没有重复。
3 个解决方案
#1
11
You can do the following!
您可以执行以下操作!
# Merging
c = a + b
=> [1, 2, 3, 4, 5, 2, 4, 6]
# Removing the value of other array
# (a & b) is getting the common element from these two arrays
c - (a & b)
=> [1, 3, 5, 6]
Dmitri's comment is also same though I came up with my idea independently.
迪米特里也发表了同样的看法，尽管我是独立想出这个主意的。
#2
14
Use Array#uniq.
使用# uniq数组。
a = [1, 3, 5, 6]
b = [2, 3, 4, 5]
c = (a + b).uniq
=> [1, 3, 5, 6, 2, 4]
#3
5
How about this．
这个怎么样。
(a | b)
=> [1, 2, 3, 4, 5, 6]
(a & b)
=> [2, 4]
(a | b) - (a & b)
[1, 3, 5, 6]
#1
11
You can do the following!
您可以执行以下操作!
# Merging
c = a + b
=> [1, 2, 3, 4, 5, 2, 4, 6]
# Removing the value of other array
# (a & b) is getting the common element from these two arrays
c - (a & b)
=> [1, 3, 5, 6]
Dmitri's comment is also same though I came up with my idea independently.
迪米特里也发表了同样的看法，尽管我是独立想出这个主意的。
#2
14
Use Array#uniq.
使用# uniq数组。
a = [1, 3, 5, 6]
b = [2, 3, 4, 5]
c = (a + b).uniq
=> [1, 3, 5, 6, 2, 4]
#3
5
How about this．
这个怎么样。
(a | b)
=> [1, 2, 3, 4, 5, 6]
(a & b)
=> [2, 4]
(a | b) - (a & b)
[1, 3, 5, 6]