MySQL在两列中比较相同的值

I have a data in my database like this :

我的数据库中有一个数据，如下所示：

jamu_a | jamu_b | khasiat

A      | B      | Z
A      | B      | X
A      | B      | C

And then, I want an output like this :

然后，我想要一个像这样的输出：

jamu_a | jamu_b | khasiat | total

A      | B      | Z, X, C | 3

I'm not expert in MySQL, what kind of query to produce an output like that? Tell me if MySQL can't do that and need some programming language. Thanks in advance

我不是MySQL的专家，产生这样的输出是什么样的查询？告诉我MySQL是否不能这样做，需要一些编程语言。提前致谢

1 个解决方案

#1

SELECT  jamu_a,
        jamu_b,
        GROUP_CONCAT(khasiat) khasiat,
        COUNT(*) total
FROM    TableName
GROUP   BY  jamu_a, jamu_b

• SQLFiddle Demo
• SQLFiddle演示
• MySQL GROUP_CONCAT()
• MySQL GROUP_CONCAT（）

OUTPUT

OUTPUT

╔════════╦════════╦═════════╦═══════╗
║ JAMU_A ║ JAMU_B ║ KHASIAT ║ TOTAL ║
╠════════╬════════╬═════════╬═══════╣
║ A      ║ B      ║ Z,X,C   ║     3 ║
╚════════╩════════╩═════════╩═══════╝

if there are repeating values on column KHASIAT and you want it to be unique, you can add DISTINCT on GROUP_CONCAT()

如果列KHASIAT上有重复值并且您希望它是唯一的，则可以在GROUP_CONCAT（）上添加DISTINCT

SELECT  jamu_a,
        jamu_b,
        GROUP_CONCAT(DISTINCT khasiat) khasiat,
        COUNT(*) total
FROM    TableName
GROUP   BY  jamu_a, jamu_b