检查字符串是否包含至少一个数字

I have got a text string like this:

我有一个这样的文本字符串:

test1test

I want to check if it contains at least one digit using a regex.

我想用正则表达式检查它是否包含至少一个数字。

What would this regex look like?

这个regex是什么样子的?

7 个解决方案

#1

I'm surprised nobody has mentioned the simplest version:

我很惊讶没有人提到最简单的版本:

\d

This will match any digit. If your regular expression engine is Unicode-aware, this means it will match anything that's defined as a digit in any language, not just the Arabic numerals 0-9.

这将匹配任何数字。如果正则表达式引擎具有unicode感知，这意味着它将匹配任何语言中定义为数字的任何东西，而不仅仅是阿拉伯数字0-9。

There's no need to put it in [square brackets] to define it as a character class, as one of the other answers did; \d works fine by itself.

不需要把它放在[方括号]中来定义为字符类，就像其他答案中的一个那样;\d本身工作正常。

Since it's not anchored with ^ or $, it will match any subset of the string, so if the string contains at least one digit, this will match.

因为它不是固定^和$,它将匹配任何子集的字符串,如果字符串包含至少一个数字,这将匹配。

And there's no need for the added complexity of +, since the goal is just to determine whether there's at least one digit. If there's at least one digit, this will match; and it will do so with a minimum of overhead.

而且，没有必要增加+的复杂性，因为目标只是确定是否有至少一个数字。如果有至少一个数字，这将匹配;这样做只需要最少的开销。

#2

The regular expression you are looking for is simply this:

您正在寻找的正则表达式简单如下:

[0-9]

You do not mention what language you are using. If your regular expression evaluator forces REs to be anchored, you need this:

你没有提到你在用什么语言。如果正则表达式求值器强制将REs固定，则需要:

.*[0-9].*

Some RE engines (modern ones!) also allow you to write the first as \d (mnemonically: digit) and the second would then become .*\d.*.

一些RE engine(现代的)也允许您将第一个写成\d(记忆:digit)，然后第二个就会变成。*\d.*。

#3

you could use look-ahead assertion for this:

您可以使用前面的断言:

^(?=.*\d).+$

#4

In Java:

在Java中:

public boolean containsNumber(String string)
{
    return string.matches(".*\\d+.*");
}

#5

This:

这样的:

\d+

should work

应该工作

Edit, no clue why I added the "+", without it works just as fine.

编辑，不知道为什么我添加了“+”，没有它也一样好。

\d

#6

Ref this

裁判这

SELECT * FROM product WHERE name REGEXP '[0-9]'

#7

In perl:

在perl中:

if($testString =~ /\d/) 
{
    print "This string contains at least one digit"
}

where \d matches to a digit.

哪里的\d匹配一个数字。

#1