如何从另一个php文件调用一个php文件的函数并将参数传递给它?

I want to call a function in one PHP file from a second PHP file and also pass two parameters to that function. How can I do this?

我想从第二个PHP文件中调用一个PHP文件中的函数，并向该函数传递两个参数。我该怎么做呢?

I am very new to PHP. So please tell me, should I include the first PHP file into the second?

我对PHP很陌生。请告诉我，我应该将第一个PHP文件包含到第二个PHP文件中吗?

Please show me an example. You can provide some links if you want.

请给我举个例子。如果你愿意，你可以提供一些链接。

3 个解决方案

#1

132

Yes include the first file into the second. That's all.

是的，将第一个文件包含到第二个文件中。这是所有。

See an example below,

请参见下面的一个例子,

File1.php :

File1。php:

<?php
  function first($int, $string){ //function parameters, two variables.
    return $string;  //returns the second argument passed into the function
  }
?>

Now Using include (http://php.net/include) to include the File1.php to make its content available for use in the second file:

现在使用include (http://php.net/include)来包含File1。php使其内容可在第二个文件中使用:

File2.php :

File2。php:

<?php
  include 'File1.php';
  echo first(1,"omg lol"); //returns omg lol;
?>

#2

file1.php

<?php

    function func1($param1, $param2)
    {
        echo $param1 . ', ' . $param2;
    }

file2.php

php

<?php

    require_once('file1.php');

    func1('Hello', 'world');

See manual

参见手册

#3

files directory:

文件目录:

Project->

项目- >

-functions.php

显然也

-main.php

functions.php

显然也

function sum(a,b){
 return a+b;
}
function product(a,b){
return a*b;
}

main.php

require_once "functions.php";
echo "sum of two numbers ". sum(4,2);
echo "<br>"; //  create break line
echo "product of two numbers ".product(2,3);

The Output Is :

的输出是:

sum of two numbers 6 product of two numbers 6

两个数字的和6两个数字的乘积6

Note: don't write public before function. Public, private, these modifiers can only use when you create class.

注意:函数前不要写public。这些修饰符只能在创建类时使用。

#1

132