Picture

时间：2021-07-14 10:20:34

Picture
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 72 Accepted Submission(s): 59
 
Problem Description
Give you the width and height of the rectangle,darw it.
Input
Input contains a number of test cases.For each case ,there are two numbers n and m (0 < n,m < 75)indicate the width and height of the rectangle.Iuput ends of EOF.
Output
For each case,you should draw a rectangle with the width and height giving in the input.
after each case, you should a blank line.
Sample Input
3 2
Sample Output
+---+

|   |

|   |

+---+
Author
xhd
Source
校庆杯Warm Up
Recommend
linle
/*

题意：画一个n*m的小盒子

初步思路：略

*/

#include<bits/stdc++.h>

using namespace std;

int n,m;

int main(){

    // freopen("in.txt","r",stdin);

    while(scanf("%d%d",&n,&m)!=EOF){

        printf("+");

        for(int i=;i<n;i++) printf("-");

        printf("+\n");

        for(int i=;i<m;i++){

            printf("|");

            for(int j=;j<n;j++){

                printf(" ");

            }

            printf("|\n");

        }

        printf("+");

        for(int i=;i<n;i++) printf("-");

        printf("+\n\n");

    }

    return ;

}

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