The code i'm trying to get to work is part of a price list of products from a db. It works almost all of it but i need one ajax to run multiple times, and it does, it even runs the success sentences but when i check the db its like it just ran once... i hope you can help me.
我试图开始工作的代码是数据库产品价格表的一部分。它几乎所有的工作,但我需要一个ajax运行多次,它确实,它甚至运行成功的句子,但当我检查数据库它就像它只运行一次...我希望你能帮助我。
I take 2 values from inputs which are id and amount of the product, and i add them to the list when a button calls the send function, this is that part of the code:
我从输入中获取2个值,即产品的id和数量,当按钮调用send函数时,我将它们添加到列表中,这是代码的一部分:
function valores(cod, cant) {
if (cod != '') {
cot.push([cod, cant]);
i++;
}
return cot;
}
function send () {
event.returnValue=false;
var id = $('#id').val();
var amount = $('#cant').val();
var total;
if ($('#total').length > 0) {
total = document.getElementById('total').value;
} else {
total = 0;
}
$.ajax({
type: 'POST',
data: ({cod : id, cant : amount, tot : total }),
url: 'process/agprods.php',
success: function(data) {
$('#totals').remove();
$('#prodsadded').append(data);
valores(id, amount);
rs = $(document.getElementById('rs').html);
},
error: function () {
$('#rs').innerHTML = rs;
document.getElementById('note').innerHTML = "Error: The product doesn't exist.";
$('#handler-note').click();
}
});
}
(I translated some words to english that are originaly in spanish and to make it more readable to you)
(我将一些单词翻译成英文,原文为西班牙文,并使其更具可读性)
So, the cot[] array keeps the product's id and amount, to use them in the next code, which runs when the list is complete and you hit a save button that calls this function:
因此,cot []数组保留产品的id和数量,以便在下一个代码中使用它们,该代码在列表完成时运行并且您点击一个调用此函数的保存按钮:
function ncotiza () {
event.returnValue=false;
var nlist = $('#codp').val();
var day = $('#days').val();
$.ajax({
async: false,
type: 'POST',
data: ({listnumber: nlist, days : day}),
url: 'process/ncot.php'
});
j = 0;
while (j <= i) {
if (cot[j][0] != 0 && cot[j][1] != 0) {
var num = cot[j][0];
var cant = cot[j][1];
$.ajax({
async: false,
type: 'POST',
data: ({ listnumber : nlist, prodid: num, amount : cant }),
url: 'process/ncotpro.php',
success: function () {
alert('Success');
}
});
cot[j][0] = 0;
cot[j][1] = 0;
j++;
}
if (j == i) {
window.location.reload(1);
alert("Finished Successfully");
};
}
}
And it all runs fine, here's the PHP:
这一切都运行良好,这是PHP:
(ncot.php)
$listnumber = isset($_POST["listnumber"]) ? $_POST["listnumber"] : '';
$days = isset($_POST["days"]) ? $_POST["days"] : '';
$cons = "INSERT INTO pricelist (listnumber, diashabiles, cdate)
VALUES ('$listnumber', '$days', CURDATE())";
mysql_query($cons);
?>
(ncotpro.php)
$listnumber = isset($_POST["listnumber"]) ? $_POST["listnumber"] : '';
$prodid = isset($_POST["prodid"]) ? $_POST["prodid"] : '';
$amount = isset($_POST["amount"]) ? $_POST["amount"] : '';
$cons = "SELECT price, um
FROM inventory
WHERE listnumber = ".$prodid;
$result = mysql_query($cons) or die ("Error: ".mysql_error());
$row=mysql_fetch_assoc($result);
$umcons = mysql_query("SELECT uvalue FROM um WHERE id = ".$row["um"]) or die ("Error:".mysql_error());
$umres = mysql_fetch_assoc($umcons);
$vuum = $umres["uvalue"];
$fprice = $row["price"] * ($amount * $vuum);
$cons = "INSERT INTO cotpro (cotizacion, producto, amount, monto)
VALUES ('$listnumber', '$prodid', '$amount', '$fprice')";
mysql_query($cons) or die ("Error: ".mysql_error());
?>
The first ajax runs ok, then it also does the one that's inside the while, and it throw all the alerts but when i check the db it just made 1 row and not all it has to.
第一个ajax运行正常,然后它也会执行while内部的那个,并且它会抛出所有警报,但是当我检查数据库时它只做了1行而不是所有它必须。
I'm sorry if it's too obvious or something, i've look a lot of questions and answers in this page and i've been trying to fix this for hours but i just dont see it.
我很抱歉,如果它太明显或什么的,我在这个页面看了很多问题和答案,我一直试图解决这个问题几个小时,但我只是没有看到它。
Thank you beforehand.
先谢谢你了。
1 个解决方案
#1
0
Try to debug the 2nd jquery file via firebug. what the value you return in i
尝试通过firebug调试第二个jquery文件。你回归的价值是什么?
while (j <= i) { .. .. .
而(j <= i){.. ..
#1
0
Try to debug the 2nd jquery file via firebug. what the value you return in i
尝试通过firebug调试第二个jquery文件。你回归的价值是什么?
while (j <= i) { .. .. .
而(j <= i){.. ..