Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive.
For example, given the range [5, 7], you should return 4.
解题思路:
本题有很多思路,最简单的方法:
result就是m和n二进制前面相同的部分!!!
JAVA实现如下:
public int rangeBitwiseAnd(int m, int n) {
int count=0;
while(m!=n){
n>>>=1;
m>>>=1;
count++;
}
return m<<count;
}