使用node.js的带有数字的字符串的正则表达式

I am using replace string using regex.

我正在使用正则表达式替换字符串。

How will i find the following string with decimal number.

我如何找到带有十进制数的以下字符串。

 Section 5.1.1
 Sections 5.1.2
 Sections 5.1.3 and 5.1.4
 Sec. 5.3.1

Can any one assist me?

任何人都可以帮助我吗?

Thanks in advance.

提前致谢。

Updated:

 (Sec(?:s\.|s|tions|tion|.)?)(&#xA0;|\s)?((\w+)?([.-]|(&#x2013;)|(&#x2014;))?(\w+))(\s+)?((\w+)?([.-]|(&#x2013;)|(&#x2014;))?(\w+))(\s+(to|and|through)\s(\w+)([.-]|(&#x2013;)|(&#x2014;))(\w+))?

1 个解决方案

#1

How about

/(^|\s)(Sec\.|Sections?) +[0-9]+(\.[0-9]+)*( +and +[0-9]+(\.[0-9]+)*)*(?=$|\s)/

It will match substrings that

它会匹配那些子串

begin with whitespace or are at the beginning of the searched string

以空格开头或位于搜索字符串的开头

are followed by whitespace or are at the end of the searched string

后跟空格或位于搜索字符串的末尾

start with Sec., Section or Sections

从Sec。,Section或Sections开始

followed by one or more spaces

然后是一个或多个空格

followed by a section number

然后是节号

optionally followed by one or more and [section number], where and is surrounded by one or more spaces.

可选地后跟一个或多个和[section number],其中和被一个或多个空格包围。

Section numbers match if they

部分编号匹配,如果他们

start with one or more digits

以一个或多个数字开头

optionally followed one or more times by a dot and again one or more digits.

可选地,一个或多个点跟随一个或多个数字。

You can trim the match to get rid of eventual whitespace at the beginning of the match.

您可以修剪匹配以在匹配开始时删除最终的空格。

Update

/(^|[^\w])(Sec\.|Sections?) +[0-9]+(\.[0-9]+)*( +and +[0-9]+(\.[0-9]+)*)*(?=$|[^\w])/

This one matches substrings that

这个匹配子串

begin with a non-word character or are at the beginning of the searched string

以非单词字符开头或位于搜索字符串的开头

are followed by a non-word character or are at the end of the searched string

后跟一个非单词字符或位于搜索字符串的末尾

Rest same as above. Use an additional replace on the match to get rid of non-word character matches at the beginning: match.replace(/^[^\w]+/, '')

休息与上面相同。在匹配项上使用额外的替换来删除开头的非单词字符匹配:match.replace(/ ^ [^ \ w] + /,'')

#1