Given a Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates.
+---------+------------+------------------+
| Id(INT) | Date(DATE) | Temperature(INT) |
+---------+------------+------------------+
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
+---------+------------+------------------+
For example, return the following Ids for the above Weather table:
+----+
| Id |
+----+
| 2 |
| 4 |
+----+
思路：
TO_DAYS(date)可以将日期转换成公元后的天数。
# Write your MySQL query statement below
select w1.Id from Weather as w1, Weather as w2
WHERE TO_DAYS(w1.Date) = TO_DAYS(w2.Date) + 1 and w1.Temperature > w2.Temperature