新意图不会第一次开始

I have 3 intents A->B->C

我有3个意图A-> B-> C.

from C to get back to A you bring up the menu and click home. This finishes B and C and opens A which in the manifest is set as a singletask.

从C回到A,你打开菜单,然后点击主页。这样就完成了B和C并打开了A,它在清单中被设置为单一任务。

This all works perfectly, but when I try to open B from A again I have to click twice on the button that starts B. Whereas when the app first opens I have to click only the once to open B

这一切都很完美,但当我再次尝试从A打开B时,我必须在启动B的按钮上单击两次。而当应用程序首次打开时,我必须单击一次才能打开B

Why could this be like this?

为什么会这样?

I think I know why. I think B is not finishing when I go from C to A. This is the code running on C

我想我知道为什么。当我从C转到A时,我认为B没有完成。这是在C上运行的代码

    Intent Intent = new Intent(this, com.home.test.Home.class);
    this.setResult(1, Intent);
    startActivity(Intent);
    this.finish();

And it should trigger this on B if I am correct

如果我是正确的话,它应该在B上触发它

    public void onActivityResult(int requestCode, int resultCode, Intent data) {
    this.finish();
}

1 个解决方案

#1

You do not need singleTask, in all likelihood. In C, when you call startActivity(), pass FLAG_ACTIVITY_CLEAR_TOP|FLAG_ACTIVITY_SINGLE_TOP as the Intent flags. That will finish C and B en route to starting A.

你很可能不需要singleTask。在C中,当您调用startActivity()时,将FLAG_ACTIVITY_CLEAR_TOP | FLAG_ACTIVITY_SINGLE_TOP作为Intent标志传递。这将完成C和B在开始A的途中。