在django中为表单自动生成表单字段

I have some models and I want to generate a multi-selection form from this data. So the form would contain an entry for each category and the choices would be the skills in that category.

我有一些模型，我想从这些数据生成一个多选形式。因此，表单将包含每个类别的条目，选择将是该类别中的技能。

models.py

models.py

class SkillCategory(models.Model):
    name = models.CharField(max_length=50)

class Skill(models.Model):
    name = models.CharField(max_length=50)
    category = models.ForeignKey(SkillCategory)

Is there a way to auto-generate the form fields? I know I can manually add a 'SkillCategory' entry in the form for each SkillCategory, but the reason to have it as a model is so skills and skillcategories can be edited freely.

有没有办法自动生成表单字段？我知道我可以在每个SkillCategory的表单中手动添加“SkillCategory”条目，但将其作为模型的原因是技能和技能类别可以*编辑。

I want to do something like this: (I tried this, but didn't get it to work, don't remember the exact error...)

我想做这样的事情:(我试过这个，但没有让它工作，不记得确切的错误...）

forms.py

forms.py

class SkillSelectionForm(forms.Form):
    def __init__(*args, **kwargs):
        super(SkillSelectionForm, self).__init__(*args, **kwargs)
        for c in SkillCategory.objects.all():
            category_skills = [(pk, s.name) for s in c.skill_set.all()]
            setattr(self, c.name, forms.MultipleChoiceField(choices=category_skills, widget=forms.CheckboxSelectMultiple))

SOLUTION

解

This creates a form field entry using the SkillCategory.name and assigns choices as those in Skill. field_name/display_name are used to avoid issues with non-ascii category names.

这将使用SkillCategory.name创建表单字段条目，并将选项分配为Skill中的选项。 field_name / display_name用于避免非ascii类别名称的问题。

forms.py

forms.py

def get_categorized_skills():
    skills = {}
    for s in Skill.objects.values('pk', 'name', 'category__name').order_by('category__name'):
        if s['category__name'] not in skills.keys():
            skills[s['category__name']] = []
        skills[s['category__name']].append((s['pk'], s['name']))
    return skills

class SkillSelectionForm(forms.Form): 
    def __init__(self, *args, **kwargs):
        super(SkillSelectionForm, self).__init__(*args, **kwargs)
        skills = get_categorized_skills()
        for idx, cat in enumerate(skills.keys()):
            field_name = u'category-{0}'.format(idx)
            display_name = cat
            self.fields[field_name] = forms.MultipleChoiceField(choices=skills[cat], widget=forms.CheckboxSelectMultiple, label=display_name)

3 个解决方案

#1

Take a look at creating dynamic forms in Django, from b-list.org and uswaretech.com. I've had success using these examples to dynamically create form content from models.

看看在Django中创建动态表单，从b-list.org和uswaretech.com。我已成功使用这些示例从模型动态创建表单内容。

#2

Okay so you can't set fields like that on forms.Form, for reasons which will become apparent when you see DeclarativeFieldsMetaclass, the metaclass of forms.Form (but not of forms.BaseForm). A solution which may be overkill in your case but an example of how dynamic form construction can be done, is something like this:

好的，所以你不能在forms.Form上设置这样的字段，原因是当你看到DeclarativeFieldsMetaclass时，会变得明显，这是form.Form的元类（但不是forms.BaseForm）。在您的情况下可能有点过分的解决方案，但是如何进行动态表单构造的示例是这样的：

base_fields = [
    forms.MultipleChoiceField(choices=[
        (pk, s.name) for s in c.skill_set.all()
    ]) for c in SkillCategory.objects.all()
]
SkillSelectionForm = type('SkillSelectionForm', (forms.BaseForm,), {'base_fields': base_fields})

#3

What you want is a Formset. This will give you a set of rows, each of which maps to a specific Skill.

你想要的是一个Formset。这将为您提供一组行，每行都映射到特定的技能。

See the Formset documentation and the page specifically on generating formsets for models.

请参阅Formset文档和专门针对模型生成表单集的页面。

#1