How can I parse fast a yyyy-mm-dd string (ie. "2010-10-14") into its year, month, and day numbers?
如何快速解析yyyy-mm-dd字符串(即“2010-10-14”)到其年,月和日数字?
A function of the following form:
以下形式的功能:
function parseDate(str) { var y, m, d; ... return { year: y, month: m, day: d }}2 个解决方案
#1
7
You can split it:
你可以拆分它:
var split = str.split('-');return { year: +split[0], month: +split[1], day: +split[2]};The + operator forces it to be converted to an integer, and is immune to the infamous octal issue.
+运算符强制它转换为整数,并且不受臭名昭着的八进制问题的影响。
Alternatively, you can use fixed portions of the strings:
或者,您可以使用字符串的固定部分:
return { year: +str.substr(0, 4), month: +str.substr(5, 2), day: +str.substr(8, 2)};#2
0
You could take a look at the JavaScript split() method - lets you're split the string by the - character into an array. You could then easily take those values and turn it into an associative array..
您可以查看JavaScript split()方法 - 让您将字符串 - 字符拆分为数组。然后,您可以轻松获取这些值并将其转换为关联数组。
return { year: result[0], month: result[1], day: result[2]}#1
7
You can split it:
你可以拆分它:
var split = str.split('-');return { year: +split[0], month: +split[1], day: +split[2]};The + operator forces it to be converted to an integer, and is immune to the infamous octal issue.
+运算符强制它转换为整数,并且不受臭名昭着的八进制问题的影响。
Alternatively, you can use fixed portions of the strings:
或者,您可以使用字符串的固定部分:
return { year: +str.substr(0, 4), month: +str.substr(5, 2), day: +str.substr(8, 2)};#2
0
You could take a look at the JavaScript split() method - lets you're split the string by the - character into an array. You could then easily take those values and turn it into an associative array..
您可以查看JavaScript split()方法 - 让您将字符串 - 字符拆分为数组。然后,您可以轻松获取这些值并将其转换为关联数组。
return { year: result[0], month: result[1], day: result[2]}