I want to make a scatterplot whose points have no fill (or equivalently, with a transparent fill).
我想制作一个散点图,其点没有填充(或等效,透明填充)。
# generate some random data for the scatterplot
n <- 5
f <- factor(1:n)
df <- expand.grid(f1 = f, f2 = f)
df <- transform(df, v1 = round(10 * runif(n ** 2)))
# plot the scatterplot
ggplot(df) + geom_point(aes(x = f1, y = f2, size = v1, fill = NA))
Setting fill
to NA
seems logical but did not work. I also tried NULL
and ""
to no avail.
将填充设置为NA似乎合乎逻辑但不起作用。我也试过NULL和“”无济于事。
2 个解决方案
#1
14
I think you want to play with shape but may be wrong:
我想你想玩形状但可能是错的:
ggplot(df) + geom_point(aes(x = f1, y = f2, size = v1), shape=1)
Or maybe...
ggplot(df) + geom_point(aes(x = f1, y = f2, size = v1), fill="green", shape=21)
if you want to fill a color.
如果你想填充颜色。
#2
0
In the later versions of ggplot (ggplot2_3.0.0) you can do the following using any shape:
在ggplot(ggplot2_3.0.0)的更高版本中,您可以使用任何形状执行以下操作:
ggplot(df) +
geom_point(aes(x = f1, y = f2, size = v1)) +
scale_shape(solid = FALSE)
#1
14
I think you want to play with shape but may be wrong:
我想你想玩形状但可能是错的:
ggplot(df) + geom_point(aes(x = f1, y = f2, size = v1), shape=1)
Or maybe...
ggplot(df) + geom_point(aes(x = f1, y = f2, size = v1), fill="green", shape=21)
if you want to fill a color.
如果你想填充颜色。
#2
0
In the later versions of ggplot (ggplot2_3.0.0) you can do the following using any shape:
在ggplot(ggplot2_3.0.0)的更高版本中,您可以使用任何形状执行以下操作:
ggplot(df) +
geom_point(aes(x = f1, y = f2, size = v1)) +
scale_shape(solid = FALSE)