Problem Description
A relay is a
race for two or more teams of runners. Each member of a team runs
one section of the race. Your task is to help to evaluate the
results of a relay race.
You have to process several teams. For each team you are given a
list with the running times for every section of the race. You are
to compute the average time per kilometer over the whole distance.
That's easy, isn't it?
So if you like the fun and challenge competing at this contest,
perhaps you like a relay race, too. Students from Ulm participated
e.g. at the "SOLA" relay in Zurich, Switzerland. For more
information visit http://www.sola.asvz.ethz.ch/ after the contest
is over.
race for two or more teams of runners. Each member of a team runs
one section of the race. Your task is to help to evaluate the
results of a relay race.
You have to process several teams. For each team you are given a
list with the running times for every section of the race. You are
to compute the average time per kilometer over the whole distance.
That's easy, isn't it?
So if you like the fun and challenge competing at this contest,
perhaps you like a relay race, too. Students from Ulm participated
e.g. at the "SOLA" relay in Zurich, Switzerland. For more
information visit http://www.sola.asvz.ethz.ch/ after the contest
is over.
Input
The first line
of the input specifies the number of sections n followed by the
total distance of the relay d in kilometers. You may safely assume
that 1 <= n <= 20 and 0.0 < d < 200.0. Every following
line gives information about one team: the team number t (an
integer, right-justified in a field of width 3) is followed by the
n results for each section, separated by a single space. These
running times are given in the format "h:mm:ss" with integer
numbers for the hours, minutes and seconds, respectively. In the
special case of a runner being disqualified, the running time will
be denoted by "-:--:--". Finally, the data on every line is
terminated by a newline character. Input is terminated by
EOF.
of the input specifies the number of sections n followed by the
total distance of the relay d in kilometers. You may safely assume
that 1 <= n <= 20 and 0.0 < d < 200.0. Every following
line gives information about one team: the team number t (an
integer, right-justified in a field of width 3) is followed by the
n results for each section, separated by a single space. These
running times are given in the format "h:mm:ss" with integer
numbers for the hours, minutes and seconds, respectively. In the
special case of a runner being disqualified, the running time will
be denoted by "-:--:--". Finally, the data on every line is
terminated by a newline character. Input is terminated by
EOF.
Output
For each team
output exactly one line giving the team's number t right aligned in
a field of width 3, and the average time for this team rounded to
whole seconds in the format "m:ss". If at least one of the team's
runners has been disqualified, output "-" instead. Adhere to the
sample output for the exact format of presentation.
output exactly one line giving the team's number t right aligned in
a field of width 3, and the average time for this team rounded to
whole seconds in the format "m:ss". If at least one of the team's
runners has been disqualified, output "-" instead. Adhere to the
sample output for the exact format of presentation.
Sample Input
2
12.5
12.5
5 0:23:21
0:25:01
0:25:01
42 0:23:32
-:--:--
-:--:--
7 0:33:20
0:41:35
0:41:35
Sample Output
5: 3:52
min/km
min/km
42: -
7: 6:00
min/km
min/km
题意：这题很水，给出总共跑几圈，每圈的用时，求出一千米多少时间；
解题思路：这个题很水，刚开始看的时候，一看输入输出就不想做了，里面有时间，很麻烦，就放到最后写，心思这用类写。。。。我去，看懂题意之后（全是脏话），这么水，就是输入输出有点难度，用cin的话可以免去很多不必要的麻烦；
感悟：水题（老师0.0，以后输入输出弄得容易看点都乱码了）
代码（G++
15MS）
15MS）
#include
#include
using namespace std;
int main()
{
//freopen("in.txt", "r", stdin);
int
n,t,h,m,s,time_s;
double
d;
bool
flag;
scanf("%d
%lf",&n,&d);
while(cin>>t)
{
flag=1;
time_s=0;
for(int i=0;i
{
char str;
cin>>str;
if(str=='-')
{
cin>>str>>str>>str>>str>>str>>str;
#include
using namespace std;
int main()
{
//freopen("in.txt", "r", stdin);
int
n,t,h,m,s,time_s;
double
d;
bool
flag;
scanf("%d
%lf",&n,&d);
while(cin>>t)
{
flag=1;
time_s=0;
for(int i=0;i
{
char str;
cin>>str;
if(str=='-')
{
cin>>str>>str>>str>>str>>str>>str;
flag=0;
continue;
}
else
{
scanf("%*c%d%*c%d",&m,&s);//%*c的意思就是跳过这个不输入了
time_s+=(s+m*60+(str-'0')*3600);
}
}
if(!flag)
printf("=: -\n", t);
else
{
int ave=1.0*time_s/d+0.5;
m=ave/60;
s=ave`;
printf("=: %d:d min/km\n", t, m, s);
}
}
return
0;
}