我想从没有替换功能的字符串中删除双引号

I want to remove Double Quote from string "Hello" word.

我想从字符串“Hello”字中删除Double Quote。

I have array var ary = ['a', 'b' , 'c'] Now when I take value from array it's return into string like if I use ary[0] = "a" but I want in value like a .

我有数组var ary = ['a','b','c']现在当我从数组中获取值时,它会返回到字符串,就像我使用ary [0] =“a”但我想要的值就像a。

Because I have One JSON file That contains

因为我有一个包含的JSON文件

{
   "a":{
       "name" : "Emma"
     },
   "b":{
       "name" : "Harry"
     },
   "c":{
       "name" : "Jonny"
     }
 }

I want value from Here using Those array like ary[0].name = Emma

我想从这里使用那些数组像ary [0] .name = Emma

NOTE : I used str.replace(/\"/gi,""); && str.replace(/"/gi,""); If any Other Idea How can I get than please Replay ASAP.

注意:我使用了str.replace(/ \“/ gi,”“); && str.replace(/”/ gi,“”);如果有任何其他想法我怎么能得到比请尽快重播。

1 个解决方案

#1

If I understood your requirement correctly, you can just use bracket notation like obj['a'].name

如果我正确理解了你的要求,你可以使用像obj ['a']这样的括号表示法

var obj = {
    a: {
        "name": "Emma"
    },
    b: {
        "name": "Harry"
    },
    c: {
        "name": "Jonny"
    }
};

var ary = ['a', 'b', 'c']

for (var i = 0; i < ary.length; i++) {
    console.log(obj[ary[i]].name)
}

Here you pass the property key as a string to the bracket notation and it will return the value

在这里,您将属性键作为字符串传递给括号表示法,它将返回值

#1