How can I use a regular expression in the substr() PHP function to get a substring matched by a pattern?
如何在substr（）PHP函数中使用正则表达式来获取模式匹配的子字符串？
Edited:
编辑：
example:
例：
$name = 'hello [*kitty*],how good is today';
I want to get what is between [....] placeholder.
我想得到[....]占位符之间的内容。
2 个解决方案
#1
35
substr() only matches whole strings. You are looking for preg_match().
substr（）只匹配整个字符串。您正在寻找preg_match（）。
Update:
更新：
$name = 'hello [*kitty*],how good is today';
preg_match( '/\[(.*?)\]/', $name, $match );
var_dump( $match );
You can find the name in $match[1]. I suggest you read up on regular expressions to understand preg_match().
您可以在$ match [1]中找到该名称。我建议你阅读正则表达式来理解preg_match（）。
#2
4
Try this:
尝试这个：
$matches = array();
preg_match("/\[([^]]*)\]/", 'hello [*kitty*],how good is today', $matches);
print_r($matches);
Oops, fixed it now :)
哎呀，现在修好:)
#1
35
substr() only matches whole strings. You are looking for preg_match().
substr（）只匹配整个字符串。您正在寻找preg_match（）。
Update:
更新：
$name = 'hello [*kitty*],how good is today';
preg_match( '/\[(.*?)\]/', $name, $match );
var_dump( $match );
You can find the name in $match[1]. I suggest you read up on regular expressions to understand preg_match().
您可以在$ match [1]中找到该名称。我建议你阅读正则表达式来理解preg_match（）。
#2
4
Try this:
尝试这个：
$matches = array();
preg_match("/\[([^]]*)\]/", 'hello [*kitty*],how good is today', $matches);
print_r($matches);
Oops, fixed it now :)
哎呀，现在修好:)