如何按名称o按日期降序排列目录列表?

I'm able to do this:

我可以这样做:

    File images = new File(path);  
    File[] imageList = images.listFiles(new FilenameFilter(){  
        public boolean accept(File dir, String name)  
        {  
            return name.endsWith(".jpg");
        }  
    });

I copied from an answer of * !

我从*的答案中复制过来!

Is there a way to listFile ok kind "directory" (folder) and to list by reverse alphabetical order ? ... And by reverse date ?

是否有一种方法可以列出ok类的“目录”(文件夹)和按反向字母顺序列出?…反过来呢?

8 个解决方案

#1

final File[] sortedFileName = images.listFiles()

if (sortedFileName != null && sortedFileName.length > 1) {
        Arrays.sort(sortedFileName, new Comparator<File>() {
             @Override
             public int compare(File object1, File object2) {
                return object1.getName().compareTo(object2.getName());
             }
    });
}

Use Array.sort() to compare the name of the files.

使用Array.sort()比较文件的名称。

Edit: Use this code to sort by date

编辑:使用此代码按日期排序

final File[] sortedByDate = folder.listFiles();

if (sortedByDate != null && sortedByDate.length > 1) {
        Arrays.sort(sortedByDate, new Comparator<File>() {
             @Override
             public int compare(File object1, File object2) {
                return (int) ((object1.lastModified() > object2.lastModified()) ? object1.lastModified(): object2.lastModified());
             }
    });
}

#2

Pointers :

指针:

File.isDirectory()

File.lastModified()

#3

The right way to order files by date of last modified in reverse mode is doing:

按最后修改日期以反向方式订购文件的正确方法是:

Arrays.sort(Files, LastModifiedFileComparator.LASTMODIFIED_REVERSE); 

for this instruction you will need the commons.io library from org.apache that you can download from here

对于这个指令，你将需要公有物。io库从org。可以从这里下载的apache

#4

you can use below code. worked for me.

您可以使用下面的代码。为我工作。

final File[] files= file.listFiles();
if (files != null && files.length > 1) {
            Collections.sort(Arrays.asList(files), new Comparator<File>() {
                public int compare(File o1, File o2) {
                    long lastModifiedO1 = o1.lastModified();
                    long lastModifiedO2 = o2.lastModified();

                    return (lastModifiedO2 < lastModifiedO1) ? -1 : ((lastModifiedO1 > lastModifiedO2) ? 1 : 0);
                }
            });
        }

#5

I was getting an exception

我有个例外

IllegalArgumentException: Comparison method violates its general contract!

例外:比较方法违反了它的一般合同!

so I used this and it worked ok:

我用了这个，效果不错

Arrays.sort(filesList, new Comparator<File>() {
   @Override
   public int compare(File a, File b) {
      if(a.lastModified() < b.lastModified() )
         return 1;
      if(a.lastModified() > b.lastModified() )
         return -1;
      return 0;
}});

#6

If you want to sort date wise then choose below code, and if you want name then already answer is above :)

如果你想按日期排序，请选择下面的代码，如果你想要名字，那么答案已经在上面了:)

File f = new File("/home/myfiles");
File [] files = f.listFiles();
Arrays.sort( files, new Comparator(){
public int compare(Object o1, Object o2) {

    if (((File)o1).lastModified() > ((File)o2).lastModified()) {
        return -1;
    } else if (((File)o1).lastModified() < ((File)o2).lastModified()) {
        return +1;
    } else {
        return 0;
    }
}
}); 

#7

I solved this problem by using this

我用这个解决了这个问题

final File[] sortedByDate = folder.listFiles();

if (sortedByDate != null && sortedByDate.length > 1) {
        Arrays.sort(sortedByDate, new Comparator<File>() {
             @Override
             public int compare(File object1, File object2) {
                return (int) ((object1.lastModified() > object2.lastModified()) ? 0: 1);
             }
    });
}

I return 0 and 1 insted of lastModified() value that solved my problem.

我返回0和1 insted的lastModified()值，它解决了我的问题。

#8

For sort based on file name,Add

对于基于文件名的排序，请添加。

object1.getName().toLowerCase(Locale.getDefault())

instead of

而不是

object1.getName()

to avoid sort issues causing by Locale changes and upper/low case filenames

避免由于语言环境更改和上/小写文件名引起的排序问题。

             final File[] sortedFileName = images.listFiles();

                if (sortedFileName != null && sortedFileName.length > 1) {
                    Arrays.sort(sortedFileName, new Comparator<File>() {
                        @Override
                        public int compare(File object1, File object2) {
                            return object1.getName().toLowerCase(Locale.getDefault()).compareTo(object2.getName().toLowerCase(Locale.getDefault()));
                        }
                    });
                }