how to assign object of interface to a protocol's object? i've a protocolA and protocolB. all the methods of both the protocols is implemented in MyClass.How to restrict the access to only protocolA's methid and protocolB's methods ?Coding is done in Objective-C for iPhone application.
如何将接口对象分配给协议的对象？我有一个protocolA和protocolB。两个协议的所有方法都是在MyClass中实现的。如何限制只访问protocolA的methid和protocolB的方法？编码是在Objective-C中为iPhone应用程序完成的。
1 个解决方案
#1
2
On object creation you can just do this:
在对象创建上，您可以这样做：
id <protocolA> protocolAObject = [[MyClass alloc] init];
Now, unless you use an explicit cast, you can't use protocolB methods.
现在，除非使用显式强制转换，否则不能使用protocolB方法。
You can also cast objects of class MyClass to either protocolA or protocolB like this:
您还可以将类MyClass的对象强制转换为protocolA或protocolB，如下所示：
MyClass *myClassObject = [[MyClass alloc] init];
id <protocolB> protocolBObject = (id <protocolB>) myClassObject;
#1
2
On object creation you can just do this:
在对象创建上，您可以这样做：
id <protocolA> protocolAObject = [[MyClass alloc] init];
Now, unless you use an explicit cast, you can't use protocolB methods.
现在，除非使用显式强制转换，否则不能使用protocolB方法。
You can also cast objects of class MyClass to either protocolA or protocolB like this:
您还可以将类MyClass的对象强制转换为protocolA或protocolB，如下所示：
MyClass *myClassObject = [[MyClass alloc] init];
id <protocolB> protocolBObject = (id <protocolB>) myClassObject;