如何在javascript中使用正则表达式替换特殊字符？

I need to replace special characters from a string, like this:

我需要从字符串中替换特殊字符，如下所示：

this.value = this.value.replace(/\n/g,'');

Except for the regex part, I need it to look for the opposite of all these:

除了正则表达式部分，我需要它来寻找所有这些的相反：

[0-9] Find any digit from 0 to 9
[A-Z] Find any character from uppercase A to uppercase Z
[a-z] Find any character from lowercase a to lowercase z

[0-9]查找0到9之间的任何数字[A-Z]查找从大写字母A到大写字母Z [a-z]的任何字符查找从小写字母a到小写字母z的任何字符

plus underscore and minus.

加上下划线和减号。

Therefore, this string is OK:

因此，这个字符串是OK：

Abc054_34-bd

Abc054_34-BD

And this string is bad:

这个字符串很糟糕：

Fš 04//4.

Fš04// 4。

From the bad string I need the disallowed characters removed.

从坏字符串我需要删除不允许的字符。

How do I stack this regex rule?

如何堆叠此正则表达式规则？

2 个解决方案

#1

You can use character class with ^ negation:

你可以使用带有^ negation的字符类：

this.value = this.value.replace(/[^a-zA-Z0-9_-]/g,'');

Tests:

测试：

console.log('Abc054_34-bd'.replace(/[^a-zA-Z0-9_-]/g,'')); // Abc054_34-bd
console.log('Fš 04//4.'.replace(/[^a-zA-Z0-9_-]/g,'')); // F044

So by putting characters in [^...], you can decide which characters should be allowed and all others replaced.

因此，通过在[^ ...]中添加字符，您可以决定应该允许哪些字符以及替换所有其他字符。

#2

Try:

尝试：

this.value = this.value.replace(/\w|-/g, '');

Reference:

参考：

Regular Expressions, at the Mozilla Developer Network.
Mozilla开发者网络上的正则表达式。

#1