有兴趣的朋友看看，一个简单的算法？计算出一个随即数组每个字符串出现的个数

计算出一个随即数组每个字符串出现的个数。



string[] str = {"aa","bb","cc","dd","aa","ff","ff","aa","cc","dd","ee","gg","cc","bb"};

以上数组里出现的字符串是不固定的。

用一种简单高效率的算法求出结果
结果
aa:3个 bb:2个 cc:3个 dd:2个 ff:2个 ee:1个 gg:1个

5 个解决方案

#1

        Dictionary<string, int> dic = new Dictionary<string, int>();
        foreach (string key in str)
        {
            if (dic.ContainsKey(key))
            {
                dic[key]++;
            }
            else
            {
                dic.Add(key, 1);
            }
        }
        System.Text.StringBuilder sb = new System.Text.StringBuilder();
        foreach (string key in dic.Keys)
        {
            sb.AppendFormat("{0}:{1}个   ",key,dic[key]);
        }

#2

引用 1 楼 flashcjy 的回复:

        Dictionary <string, int> dic = new Dictionary <string, int>();
        foreach (string key in str)
        {
            if (dic.ContainsKey(key))
            {
                dic[key]++;
            }
            else
            {
                dic.Add(key, 1);
            }
        }
        System.Text.StringBuilder sb = new System.Text.StringBuilder();
        foreach (string key in dic.Keys)
        {
            sb.AppendFormat("{0}:{1}个  ",key,dic[key]);
        }

#3

这种问题用Linq最简单...

var groups = str.GroupBy(s => s).ToDictionary(d => d.Key, d => d.Count());

foreach (var item in groups)

{

    Console.WriteLine("{0}:{1}", item.Key, item.Value);

}

#4

1楼的比较正规，我给个没技术含量的linq！

using System;
using System.Linq;

namespace ConsoleApplication4
{
    class Program
    {
        static void Main(string[] args)
        {
            string[] strs = { "aa", "bb", "cc", "dd", "aa", "ff", "ff", "aa", "cc", "dd", "ee", "gg", "cc", "bb" };
            var g = from item in strs group item by item into groups select groups;

            foreach (var item in g)
                Console.Write("{0}:{1}个 ", item.Key, item.Count());
        }
    }
}

#5

学习学习。谢谢！

#1

#2